我已经被困在这个问题上有一段时间了,目标是创建一个数组来容纳卡片,一旦我创建了数组,就把它们打印出来,唯一正在打印的卡片就是红心之王。为什么不迭代?
public class Card
{
// Card suits (provided for your convenience - use is optional)
public static final int SPADES = 0;
public static final int HEARTS = 1;
public static final int CLUBS = 2;
public static final int DIAMONDS = 3;
// Card faces (provided for your convenience - use is optional)
public static final int ACE = 1;
public static final int TWO = 2;
public static final int THREE = 3;
public static final int FOUR = 4;
public static final int FIVE = 5;
public static final int SIX = 6;
public static final int SEVEN = 7;
public static final int EIGHT = 8;
public static final int NINE = 9;
public static final int TEN = 10;
public static final int JACK = 11;
public static final int QUEEN = 12;
public static final int KING = 13;
// define fields here
private static int suit;
private static int val;
private String[] suits = {"Clubs", "Spades", "Diamonds", "Hearts"};
private String[] vals = {"Ace","2", "3", "4", "5", "6", "7",
"8", "9", "10", "Jack", "Queen", "King" };
// This constructor builds a card with the given suit and face, turned face down.
public Card(int suit, int val)
{
this.val = val;
this.suit = suit;
}
public @Override String toString()
{
return vals[val] + " Of " + suits[suit];
}
// This method retrieves the suit (spades, hearts, etc.) of this card.
public int getSuit()
{
return this.suit;
}
// This method retrieves the face (ace through king) of this card.
public int getFace()
{
// return this.val;
switch(val)
{
case 0 : return 1;
case 1 : return 2;
case 2 : return 3;
case 3 : return 4;
case 5 : return 6;
case 6 : return 7;
case 7 : return 8;
case 8 : return 9;
case 9 : return 10;
case 10 : return 10;
case 12 : return 10;
default : return 0;
}
}
}`
import java.util.ArrayList;
import java.util.Random;
// This class represents the deck of cards from which cards are dealt to players.
public class Deck
{
//array
public static Card[] cards;
// private static ArrayList<Card> cards;
int i;
int counter;
// This constructor builds a deck of 52 cards.
Deck()
{
i = 51;
//array implementation
cards = new Card[52];
int x = 0;
for(int i = 0; i < 4; i++)
{
for(int j = 0; j < 13;j++)
{
//Array implementation
cards[x] = new Card(i,j);
x++;
}
}
}
// This method takes the top card off the deck and returns it.
public Card deal()
{
//Array implementation
int index = 0;
Card temp = cards[index];
return temp;
}
// this method returns true if there are no more cards to deal, false otherwise
public boolean isEmpty()
{
if(cards.length == 0)
{
return true;
}
return false;
}
//this method puts the deck int some random order
// public void shuffle()
// {
// for(int i = 51; i > 0; i--)
// {
// int rand = (int) (Math.random() * (i+1));
// Card temp = this.cards[i];
// this.cards[i] = cards[rand];
// cards[rand] = temp;
// }
//
// }
}
public class BlackJack extends Deck
{
public static void main(String []args)
{
System.out.println("Ready to play a game of BlackJack?");
Deck deck = new Deck();
for(int i = 0; i < cards.length;i++)
{
System.out.println(cards[i]);
}
最佳答案
问题是由以下原因引起的:
// define fields here
private static int suit;
private static int val;
因为它们是静态的,所以所有 Card 实例都共享它们,因此它们都将具有最后设置的值。消除静电。
关于java - 创建一副牌并洗牌,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33837989/