java else 没有 if 错误

Question

我用java写了这个，并且不断得到else而没有if错误。我检查了一遍又一遍，找不到错误。如果程序的其余部分有问题，这真的是缺失吗？

public class Password {

     public static void main(String[] args) {

        //int Counter = 0;

         String[] UserName = {
            "William Whitcomb" , "Pamela Healy" ,
            "Dennis Clark" , "Troy Bingham" ,
            "Bill Mauler"
         };
        String[] Password = {
            "WWhit0523" , "PHeal0854" ,
            "DClar1053" , "TBing1272" ,
            "BMaul0968"
         };
          String EnterName = JOptionPane.showInputDialog ( "Enter a valid user name.",     //Name pane window
          "User Name");
          String EnterPassword = JOptionPane.showInputDialog ( "Enter a valid password.",       //Age pane window
          "Password");
          for (int Counter = 0; Counter < UserName.length;){
            Validate();
            if (Validate() = true) {
                JOptionPane.showMessageDialog (null, "You entered the User Name of " + UserName[Counter] +
                "and the password of " + Password[Counter]);  //Results pane
                }
            }   //End of for
        }  //End of Method


        Boolean Validate(String EnterName , String EnterPassword){
                Boolean Condition = false;

                    if (EnterName.equals(UserName[Counter])) {
                        if (EnterPassword.equals(Password[Counter])) {
                        Condition = true;
                        return //Condition;
                        } else {
                            JOptionPane.showMessageDialog (null, "You have entered an invalid password.");
                            Counter += 1;
                                }    //End of Inner Else

                    } else {
                        JOptionPane.showMessageDialog (null, "You have entered an invalid user name.");
                        Counter += 1;
                        }  //End of Outer Else
                } //End of outer if
            }  //End of Method
    }   //End of Class

Answer 1

我认为问题出在这一行:

return //Condition;

您不小心注释掉了分号，从而引发了不相关的解析错误。

在某种程度上相关的说明中，当您的函数返回 boolean 时，您不应将结果与 true 或 false 进行比较。只需编写 if (Validate())... 或 if (!Validate())... 即可。