我对此很陌生，但我正在尝试做一个酒店预订程序。
所以我有一个包含所有房间的 2D int 数组，当我启动程序时，我希望它们随机洗牌到一个名为 RoomNotInUse 或 RoomInUse 的数组中(所以每当我启动程序时，房间都是随机生成的。
如果有人知道解决这个问题的方法那就太棒了:)
// ARRAYS
protected static int[][] rooms = {
{1,1}, {1,2}, {1,3}, {1,4}, {1,5},
{2,1}, {2,2}, {2,3}, {2,4}, {2,5},
{3,1}, {3,2}, {3,3}, {3,4}, {3,5},
{4,1}, {4,2}, {4,3}, {4,4}, {4,5},
{5,1}, {5,2}, {5,3}, {5,4}, {5,5}
};
//Declare all hotel rooms 5x5, the first number is the floor and the sec is the room
private char[][] ROIU = {
};
//Rooms not in use
private char[][] RIU = {
};
//Rooms in use
public class roomShuffle {
}
//Shuffle all rooms in 2 diffrent arrays, ROIN and RIU
public class RoomNotInUse {
}
//Displayes all the rooms thats not in use
public class RoomInUse {
}
//Displayes all rooms in use
}
最佳答案
您可以使用针对二维数组修改的 Fisher–Yates 算法:
void shuffle(int[][] a) {
Random random = new Random();
for (int i = a.length - 1; i > 0; i--) {
for (int j = a[i].length - 1; j > 0; j--) {
int m = random.nextInt(i + 1);
int n = random.nextInt(j + 1);
int temp = a[i][j];
a[i][j] = a[m][n];
a[m][n] = temp;
}
}
}
关于java - 2D int 数组洗牌，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/20190110/