我尝试从 Google Places API 获取地点，但没有获得任何值。我总是遇到同样的错误，但我不知道为什么。
public JSONObject getJSONFromUrl() {
URL url;
HttpsURLConnection urlConnection;
JSONObject result = new JSONObject();
// Making HTTP request
try {
//Define connection
url = new URL("https://maps.googleapis.com/maps/api/place/nearbysearch/json");
urlConnection = (HttpsURLConnection)url.openConnection();
urlConnection.setRequestMethod("POST");
//urlConnection.setRequestProperty("Content-Type", "application/json");
urlConnection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
urlConnection.setRequestProperty("charset", "utf-8");
urlConnection.setRequestProperty("Accept", "application/json");
urlConnection.setDoOutput(true);
urlConnection.setDoInput(true);
urlConnection.setUseCaches(false);
Log.d(TAG, "Conexión establecida");
//Send data
String parameters = "?location=38.26,-0.70";
parameters+="&radius=5000";
parameters+="&key=API_KEY_SERVER_APPLICATIONS";
parameters+="&types=restaurant";
OutputStreamWriter wr= new OutputStreamWriter(urlConnection.getOutputStream(), "UTF-8");
wr.write(parameters);
wr.flush();
wr.close();
Log.d(TAG, "Datos enviados");
Log.d(TAG, "ResponseCode: " + String.valueOf(urlConnection.getResponseCode()));
//Display what returns POST request
StringBuilder sb = new StringBuilder();
int HttpResult = urlConnection.getResponseCode();
if(HttpResult == HttpURLConnection.HTTP_OK){
String json;
BufferedReader br = new BufferedReader(new InputStreamReader(urlConnection.getInputStream(),"utf-8"));
String line;
while ((line = br.readLine()) != null) {
sb.append(line + "\n");
}
br.close();
//System.out.println(""+sb.toString());
Log.d(TAG, "sb: " + sb.toString());
json = sb.toString();
Log.e("JSON", json);
// Parse the String to a JSON Object
result = new JSONObject(json);
}else{
//System.out.println(urlConnection.getResponseMessage());
Log.d(TAG, "urlConnection.getResponseMessage(): " + urlConnection.getResponseMessage());
result = null;
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
Log.d(TAG, "UnsuppoertedEncodingException: " + e.toString());
} catch (JSONException e) {
e.printStackTrace();
Log.d(TAG, "Error JSONException: " + e.toString());
} catch (IOException e) {
e.printStackTrace();
Log.d(TAG, "IOException: " + e.toString());
}
// Return JSON Object
return result;
}
我总是遇到的错误是:
06-22 15:42:08.456: D/GetDataFromURL(22138): ResponseCode: 200
06-22 15:42:08.462: D/GetDataFromURL(22138):
sb: {
06-22 15:42:08.462: D/GetDataFromURL(22138): "error_message" : "This service requires an API key.",
06-22 15:42:08.462: D/GetDataFromURL(22138): "html_attributions" : [],
06-22 15:42:08.462: D/GetDataFromURL(22138): "results" : [],
06-22 15:42:08.462: D/GetDataFromURL(22138): "status" : "REQUEST_DENIED"
}
注意:之前，我创建了一个 API KEY(如“服务应用程序 key ”)和其他 API key (如“Android 应用程序 key ”)并使用两者进行了测试？我使用的 API key 是服务器应用程序的 API key 。
最佳答案
关于java - 从 Google 地方信息获取数据时出错，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/30979635/