java - onetomany 集合持有者的版本控制失败

Question

给定父实体

@Entity
public class Expenditure implements Serializable {
...
    @OneToMany(mappedBy = "expenditure", cascade = CascadeType.ALL, orphanRemoval = true)
    @OrderBy()
    private List<ExpenditurePeriod> periods = new ArrayList<ExpenditurePeriod>();

    @Version
    private Integer version = 0;
...
}

和 child 一

@Entity
public class ExpenditurePeriod implements Serializable {
...
    @ManyToOne
    @JoinColumn(name="expenditure_id", nullable = false)
    private Expenditure expenditure;
...
}

在一个事务中更新父级和子级时，会抛出 org.hibernate.StaleObjectStateException:行已被另一事务更新或删除(或未保存值映射不正确):

事实上，hibernate 发出两个 sql 更新:一个更改父属性，另一个更改子属性。您知道一种摆脱父更新更改子的方法吗？更新会导致乐观锁效率低下和误报。请注意，子级和父级都正确地将其状态保存在数据库中。

Hibernate 版本为 3.5.1-Final

Answer 1

(...) Indeed, hibernate issues two sql updates: one changing parent properties and another changing child properties.

如果您在一个事务中更新了父级和子级，这不是预期的结果吗？

Do you know a way to get rid of parent update changing child? The update results both in inefficiency and false positive for optimistic lock.

我不明白这个问题，也无法重现它。以下测试方法(在事务内运行)适合我(由于我修改了父项和一个子项，它按预期生成了两个更新)。

@Test
public void testUpdate() {
    Expenditure expenditure = new Expenditure();
    ExpenditurePeriod expenditurePeriod1 = new ExpenditurePeriod();
    ExpenditurePeriod expenditurePeriod2 = new ExpenditurePeriod();

    expenditure.getPeriods().add(expenditurePeriod1);
    expenditure.getPeriods().add(expenditurePeriod2);
    expenditurePeriod1.setExpenditure(expenditure);
    expenditurePeriod2.setExpenditure(expenditure);

    em.persist(expenditure);
    em.flush();

    assertNotNull(expenditure.getId());
    assertNotNull(expenditurePeriod1.getId());
    assertNotNull(expenditurePeriod2.getId());
    assertEquals(Integer.valueOf(0), expenditure.getVersion());
    assertEquals(Integer.valueOf(0), expenditurePeriod1.getVersion());
    assertEquals(Integer.valueOf(0), expenditurePeriod2.getVersion());

    expenditure.setProperty("a");
    expenditurePeriod1.setProperty("b");

    em.merge(expenditure);
    em.flush();

    assertEquals(Integer.valueOf(1), expenditure.getVersion());
    assertEquals(Integer.valueOf(1), expenditurePeriod1.getVersion());
    assertEquals(Integer.valueOf(0), expenditurePeriod2.getVersion());
}

如果这不能代表您的情况，请澄清。