我正在浏览 tutorial在 redis 上遇到了一个没有意义的命令。从我下面的代码中，我得到了一个肯定仍然存在的 key 的 -2 生存时间返回值。我的代码不应该返回一个永不过期的 -1 吗？
教程说:
Redis can be told that a key should only exist for a certain length of time. This is accomplished with the EXPIRE and TTL commands.
SET resource:lock "Redis Demo" EXPIRE resource:lock 120
This causes the key resource:lock to be deleted in 120 seconds. You can test how long a key will exist with the TTL command. It returns the number of seconds until it will be deleted.
TTL resource:lock => 113 // after 113s TTL resource:lock => -2
The -2 for the TTL of the key means that the key does not exist (anymore). A -1 for the TTL of the key means that it will never expire. Note that if you SET a key, its TTL will be reset.
SET resource:lock "Redis Demo 1"
EXPIRE resource:lock 120
TTL resource:lock => 119
SET resource:lock "Redis Demo 2"
TTL resource:lock => -1
这是我在交互式终端中输入的代码。我的假设是第 3 行应该返回 -1，表示永不过期。我从来没有设置过期时间，所以我不知道为什么我会返回 -2。
> SET loggedIn "True"
OK
> TTL logggedIn
(integer) -2
> GET loggedIn
"True"
最佳答案
您有一个拼写错误:您设置了一个名为 loggedIn 的键，同时试图获取 loggedIn 的 TTL>
关于redis - 初学者 Redis 命令，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/40809751/