java - JPA 中的继承不起作用

Question

我有一个父类:

@MappedSuperclass
public class BaseText implements Serializable {

    @Column(name = "LOCALE_CODE", nullable = false)
    private String localeCode;

    @ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    @Index
    @Column(name = "LOCALIZED_TEXT_ID", nullable = false)
    @ForeignKey
    private LocalizedText localizedText;

    //getters and setters 
}

以及子类之一:

@Entity
@Table(name = "ASSESSMENT_TEXT")
@AttributeOverride(name = "localeCode", column = @Column(name = "LOCALE_CODE"))
@AssociationOverride(name = "localizedText", joinColumns = @JoinColumn(name = "LOCALIZED_TEXT_ID"))
public class AssessmentText extends BaseText {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "ID")
    private Long id;

    @ManyToOne(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
    @Index
    @Column(name = "ASSESSMENT_ID", nullable = false)
    @ForeignKey
    private Assessment assessment;

    //Getters and setters.
}

当我尝试保留一个对象时，出现以下错误:

org.apache.openjpa.persistence.ArgumentException: Superclass field "java.lang.Object.localizedText" is mapped in the metadata for subclass "com.my.com.AssessmentText", but is not a persistent field.

是什么原因造成的以及如何解决？

我在 JUnit 中使用嵌入式 derby 数据库，JPA 实现是 OpenJPA。

Answer 1

我不确定这是否是解决方案，但我错过了来自 AssessmentText 的 @Inheritance 注释:

@Entity
@Table(name = "ASSESSMENT_TEXT")
@Inheritance(strategy=InheritanceType.JOINED)
@AttributeOverride(name = "localeCode", column = @Column(name = "LOCALE_CODE"))
@AssociationOverride(name = "localizedText",
                     joinColumns = @JoinColumn(name = "LOCALIZED_TEXT_ID"))
public class AssessmentText extends BaseText {