java - 如何在两个线程之间来回切换

Question

我在两个不同的类中有两个方法，就像这样

public class ClassX implements Runnable {

    public  void methodAandB() {
        for(int i=0;i<10;i++) {
            System.out.println("This is A and B ");
        }
    }
    @Override
    public void run() {
        methodAandB();
    }
}

<小时/>

public class ClassY implements Runnable {

    public void methodAorB() {
        for(int i=0;i<10;i++) {
            System.out.println("This is A or B");
        }
    }

    @Override
    public void run() {
        methodAorB(a);
    }
}

线程t1正在调用methodAandB()。

线程t2正在调用methodAorB()。

<小时/>

我可以在方法中的每次循环迭代后在这两个线程之间切换吗？

我想得到这样的输出:

This is A and B

This is A or B

This is A and B

This is A or B

This is A and B

This is A or B

This is A and B

This is A or B

Answer 1

线程之间触发器的最佳示例:

给定两个 int 数组(偶数和奇数)，2 个线程按自然顺序打印它们的数字。

package com.rough;

public class ThreadsBehaviour {

    static Object lock = new Object();

    public static void main(String[] args) throws InterruptedException {

        int a[] = {1,3,5,7,9};
        int b[] = {2,4,6,8,10};

        Thread odd = new Thread(new Looper(a, lock));
        Thread even = new Thread(new Looper(b, lock));

        odd.start();
        even.start();
    }

}

class Looper implements Runnable
{

    int a[];
    Object lock;

    public Looper(int a[], Object lock)
    {
        this.a = a;
        this.lock = lock;
    }
    @Override
    public void run() {

        for(int i = 0; i < a.length; i++)
        {
            synchronized(lock)
            {

                System.out.print(a[i]);
                try 
                {
                    lock.notify();
                    if(i == (a.length - 1))
                    {
                        break;
                    }
                    lock.wait();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
        }

    }

}