javascript - 避免同一链接出现多个新选项卡

Question

var mywin = null;
var mywin1 = null;
var mywin2 = null;
var mywin3 = null;
chrome.browserAction.onClicked.addListener(function () {
  if (mywin == null || mywin.closed) {
    mywin = window.open('https://google.com');
  } else {
    mywin.focus();
  }
  if (mywin1 == null || mywin1.closed) {
    mywin1 = window.open("https://facebook.com");
  } else {
    mywin1.focus();
  }
  if (mywin2 == null || mywin2.closed) {
    mywin2 = window.open("https://youtube.com");
  } else {
    mywin2.focus();
  }
  if (mywin3 == null || mywin3.closed) {
    mywin3 = window.open("https://gmail.com");
  } else {
    mywin3.focus();
  }
});

this code avoid the duplicate new tab when tab already open but this code work correctly when click but after some time i try to click it will open all tab again pls help me

Answer 1

将第二个参数name传递给window.open("http://facebook.com", "fbwin");

有关 window.open 的更多信息可以在这里找到... http://www.w3schools.com/jsref/met_win_open.asp