javascript - 如何从 $httpProvider 拦截器的 'reponse' 函数抛出错误

Question

我正在用 Angular 制作一个http拦截器，我想从$httpProvider拦截器的response抛出错误。

根据文档:

response: interceptors get called with http response object. The function is free to modify the response object or create a new one. The function needs to return the response object directly, or as a promise containing the response or a new response object.

responseError: interceptor gets called when a previous interceptor threw an error or resolved with a rejection.

我想执行上面引用中的粗体部分，以便将状态为 200 的响应(我有一个条件)路由到 responseError ，我将在其中处理错误。 不返回响应会引发以下错误:

Cannot read property 'data' of undefined

我不想返回响应，但想将其传递给下一个处理程序，即 responseError。

我怎样才能做到这一点？ 我希望我说清楚了。 谢谢。

更新(下面的代码):

app.config(['$httpProvider', function($httpProvider) {
    interceptor.$inject = ['$q', '$rootScope'];
    $httpProvider.interceptors.push(interceptor);

    function interceptor($q, $rootScope) {
        return {
            response: response,
            responseError: responseError
        };

        function response(response) {
            if (response.data.rs == "F") {
                // I want to route it responseError -->
            } else {
                return response;
            }
        }

        function responseError(response) {
            // I want to handle that error here
        }
    }

}]);

Answer 1

用途:

return $q.reject(response);

还要确保您返回:(阅读相关内容 here )

返回响应|| $q.when(响应);

而不是:

return response;