数据未显示。我尝试在调试器中调试cide。我收到错误 $.jqx.dataAdapter is not a constructor
数据已成功填充到 aDataSet
中。请告诉我什么可能是错误的。
$(document).ready(function(){
var aDataSet = [
//loading data --successful
];
var source =
{
localdata: aDataSet,
datatype: "array",
dataFields:
[
{ name: 'empcode', type: 'string' },
{ name: 'srno', type:'number'},
{ name: 'projectcode', type: 'string' },
{ name: 'projectname', type: 'string' },
{ name: 'startdate', type: 'date' },
{ name: 'enddate', type: 'date' },
{ name: 'clientname', type: 'string' },
{ name: 'status', type: 'string' },
{ name: 'modify', type: 'string' },
{ name: 'delete', type: 'string' },
{ name: 'view', type: 'string' }
]
};
var dataAdapter = new $.jqx.dataAdapter( this.source ,{
loadComplete: function (aDataSet) { },
loadError: function (xhr, status, error) { }
});
// create jqxDataTable.
$("#tableid").jqxDataTable(
{
source: dataAdapter,
pageable: true,
altRows: true,
filterable: true,
height: 400,
filterMode: 'advanced',
width: 850,
columns: [
{ text: 'Sr No', cellsAlign: 'center', align: 'center', dataField: 'srno', width: 200 },
{ text: 'Emp Code', cellsAlign: 'center', align: 'center', dataField: 'empcode', width: 200 },
{ text: 'Project Code', dataField: 'Quantity', cellsformat: 'd', cellsAlign: 'center', align: 'center', width: 100 },
{ text: 'Project Name', dataField: 'Price', cellsformat: 'c2', align: 'center', cellsAlign: 'center', width: 70 },
{ text: 'Start Date', cellsAlign: 'center', align: 'center', dataField: 'startdate', width: 100 },
{ text: 'End Date', cellsAlign: 'center', align: 'center', dataField: 'enddate',width: 100 },
{ text: 'Client Name', cellsAlign: 'center', align: 'center', dataField: 'enddate',width: 100 },
{ text: 'Status', cellsAlign: 'center', align: 'center', dataField: 'status',width: 100 },
{ text: 'Modify', cellsAlign: 'center', align: 'center', dataField: 'modify',width: 100 },
{ text: 'Delete', cellsAlign: 'center', align: 'center', dataField: 'delete',width: 100 },
{ text: 'View', cellsAlign: 'center', align: 'center', dataField: 'view',width: 100 }
]
});
});
最佳答案
如果你显示你的 HTML,而不仅仅是你的 JS,那就更好了,这样我们就可以看看你是否有同样的问题。我遇到了同样的问题,解决方案是添加对 jqxdata 的引用,如下所述:
https://www.jqwidgets.com/community/topic/b-jqx-dataadapter-is-not-a-constructor/
例如,我试图将 jqx-data-table 添加到网站中。最初我在引用文献中有这个(Jquery 和其他引用文献在其他地方):
<script src="~/js/jqwidgets/jqxbuttons.js"></script>
<script src="~/js/jqwidgets/jqxscrollbar.js"></script>
<script src="~/js/jqwidgets/jqxdatatable.js"></script>
<script src="~/js/jqwidgets/jqxmenu.js"></script>
<script src="~/js/jqwidgets/jqxlistbox.js"></script>
<script src="~/js/jqwidgets/jqxdropdownlist.js"></script>
所以我只是在一开始就添加了这个:
<script src="~/js/jqwidgets/jqxdata.js"></script>
结果:
<script src="~/js/jqwidgets/jqxdata.js"></script>
<script src="~/js/jqwidgets/jqxbuttons.js"></script>
<script src="~/js/jqwidgets/jqxscrollbar.js"></script>
<script src="~/js/jqwidgets/jqxdatatable.js"></script>
<script src="~/js/jqwidgets/jqxmenu.js"></script>
<script src="~/js/jqwidgets/jqxlistbox.js"></script>
<script src="~/js/jqwidgets/jqxdropdownlist.js"></script>
关于javascript - $.jqx.dataAdapter 不是构造函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44627574/