看下面的例子:
class Parent {
constructor({ parentOnlyArg = 'default value' } = {}) {
this.parentOnlyArg = parentOnlyArg;
}
}
class Child extends Parent {
// this class and also any class inheriting from it
constructor({ visibleStyle = 'inline' } = {}) {
// I want to pass argument to super as an object
super(/** args **/);
this.visibleStyle = visibleStyle;
}
}
class Child2 extends Parent {
// Specifying parentOnlyArg as default will change the behaviour
constructor({ parentOnlyArg = 'another parent value',
someOther = 'value' } = {}) {
// I want to pass argument to super as an object
super(/** args **/);
this.someOther = someOther;
}
}
是否可以将构造函数参数传递给 super?
看起来比我想象的要简单
super(...arguments);
然后我可以使用创建Child
var c1 = new Child(); // c.parentOnlyArg = 'default value'
var c2 = new Child2(); // c.parentOnlyArg = 'another parent value'
var c3 = new Child({ parentOnlyArg: 'changed again' }); // c.parentOnlyArg = 'changed again'
最佳答案
您可以使用object destructuring with rest properties 。浏览器尚未实现,但 BabelJs可以转译它。
function assertEmpty(obj) {
if (Object.keys(obj).length > 0) {
throw new Error("Unexpected parameters");
}
}
class A {
constructor({ a = "foo", ...rest } = {}) {
assertEmpty(rest);
console.log("new A " + a);
}
}
class B extends A {
constructor({ b = "bar", ...rest } = {}) {
super(rest);
console.log("new B " + b);
}
}
new B({a:2}); // prints 'new A 2', 'new B bar'
new B({a:4, b:5, c:6}); // throws 'Unexpected parameters'
在上面的代码片段中,父类看不到后代消耗的参数。如果您遇到问题,可以按照@Bergi 或@loganfsmyth 的建议进行操作。例如:
class A {
constructor(params = {}) {
const { a = "foo" } = params;
console.log("a=" + a);
}
}
class B extends A {
constructor(params = {}) {
const { b = "bar" } = params;
super(params);
console.log("b=" + b);
}
}
new B({a:2}); // prints a=2 b=bar
new B({b:5}); // prints a=foo b=5
关于javascript - ES6 将对象传递给构造函数并设置属性,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44887848/