javascript - 拼接出数据，未知位置

Question

我有一个待办事项列表，使用 localStorage...我需要能够从待办事项列表中删除该项目...我尝试使用“dataArray.splice();”但问题是我不知道当位置未知时如何删除对象......

function getTodoItems() {
    for (var i = 0; i < dataArray.length; i++) {
        if (!dataArray[i].listItem.length) return;
        var itemList = document.getElementById("my-todo-list");
        var list = document.createElement("li");
        itemList.appendChild(list);
        list.innerHTML = dataArray[i].listItem;
        var spanItem = document.createElement('span');
        spanItem.style.float = 'right';
        var myCloseSymbol = document.createTextNode('\u00D7');
        spanItem.classList.add("closeBtn");
        spanItem.appendChild(myCloseSymbol);
        listItems[i].appendChild(spanItem);
        close[i].onclick = function() {
            var div = this.parentElement;
            div.style.display = "none";
            console.log(dataArray);
        }
        var list = document.getElementsByTagName('li');
        list[i].onclick = function() {
            this.classList.toggle("checked");
        }
    }
}

Answer 1

然后大概得到它的位置:

 const position = dataArray.indexOf(/*whatever*/);
 dataArray.splice(position, 1);