我有一个代码(下面的片段),但我不明白为什么单击按钮时,它仅显示第一个下拉菜单的菜单。单击第二个按钮时,它什么也不做。
有什么想法吗?
谢谢
document.querySelector("[data-toggle=dropdown]").addEventListener("click", function() {
document.querySelector(this.getAttribute("data-target")).classList.toggle("d-block");
});
.dropdown {
position: relative;
display: inline-block;
}
.dropdown-menu {
position: absolute;
top: 100%;
left: 0;
display: none;
float: left;
min-width: 10rem;
padding: 0.5rem 0;
margin: 0.125rem 0 0;
font-size: 1rem;
text-align: left;
background: #f8f9fa;
border-radius: 0.25rem;
z-index: 1;
box-shadow: 0 0.1875rem 0.375rem rgba(0, 0, 0, 0.16), 0 0.1875rem 0.375rem rgba(0, 0, 0, 0.23);
}
.dropdown-item {
display: block;
padding: 0.25rem 1rem;
white-space: nowrap;
}
.d-block {
display: block
}
<div class="dropdown">
<button data-toggle="dropdown" data-target="#test" class="btn btn-success">Dropdown</button>
<div id="test" class="dropdown-menu"><a class="dropdown-item">Item</a><a class="dropdown-item">Item</a></div>
</div>
<div class="dropdown">
<button data-toggle="dropdown" data-target="#test1" class="btn btn-success">Dropdown</button>
<div id="test1" class="dropdown-menu"><a class="dropdown-item">Item</a><a class="dropdown-item">Item</a></div>
</div>
最佳答案
一个简单的解决方案,至于为什么你的代码不起作用,你通过使用querySelector
定位单个 dom对象,如下这将获取第一个满足查询要求的 dom 对象。而 querySelectorAll
将抓取满足查询要求的所有元素,希望这在一定程度上有所帮助。
编辑
我已经添加了该功能,这样如果您单击下拉菜单两次,它将隐藏当前的下拉菜单! :)
var list = document.querySelectorAll("[data-toggle=dropdown]");
for (var i = 0, s = list.length; i< s; i ++) {
var elm = list[i];
elm.addEventListener("click", function() {
// this for loop will hide previously clicked drop downs
for (var j = 0, z = list.length; j < z; j++) {
if (list[j] != this) {
var elm = document.querySelector(list[j].getAttribute("data-target"));
var str = elm.className.replace("d-block");
elm.className = str;
}
} // if you like, remove the above loop
var obj = document.querySelector(this.getAttribute("data-target"));
if (obj.className.indexOf("d-block") > 0) {
var temp = obj.className.replace("d-block", "");
obj.className = temp;
} else { obj.className += " d-block"; }
});
}
.dropdown {
position: relative;
display: inline-block;
}
.dropdown-menu {
position: absolute;
top: 100%;
left: 0;
display: none;
float: left;
min-width: 10rem;
padding: 0.5rem 0;
margin: 0.125rem 0 0;
font-size: 1rem;
text-align: left;
background: #f8f9fa;
border-radius: 0.25rem;
z-index: 1;
box-shadow: 0 0.1875rem 0.375rem rgba(0, 0, 0, 0.16), 0 0.1875rem 0.375rem rgba(0, 0, 0, 0.23);
}
.dropdown-item {
display: block;
padding: 0.25rem 1rem;
white-space: nowrap;
}
.d-block {
display: block
}
<div class="dropdown">
<button data-toggle="dropdown" data-target="#test" class="btn btn-success">Dropdown</button>
<div id="test" class="dropdown-menu"><a class="dropdown-item">Item</a><a class="dropdown-item">Item</a></div>
</div>
<div class="dropdown">
<button data-toggle="dropdown" data-target="#test1" class="btn btn-success">Dropdown</button>
<div id="test1" class="dropdown-menu"><a class="dropdown-item">Item</a><a class="dropdown-item">Item</a></div>
</div>
关于javascript - 具有数据属性的多个下拉菜单切换,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48832394/