javascript - 为什么 "Building"不是构造函数，而 "Resource"是？

Question

function Resource(name = "undefined", count= 0) {
  this.name = name;
  this.count= count;
}

function Building(name = "undefined", count= 0, cost= 0) {
  this.name = name;
  this.count= count;
  this.cost= cost;
}

function NewBuilding(name) {
  Building[Buildz] = new Building(name);
  createBuildingBtn(name);
  Buildz++;
}

function NewResource(name) {
  Res[Resz] = new Resource(name);
  createResourceDiv(name);
  Resz++;
}

嗯，我有这段代码，“构建”几乎与资源完全相同。资源有效，但建筑无效。好吧，我希望你能帮助我。

Answer 1

您在同一范围内有一个名为 Building 的函数和一个名为 Building 的数组。将您的数组名称更改为其他名称即可。 Resource 之所以有效，是因为您为其附带的数组 (Res) 使用了不同的名称。

Builds = [];
Res = []
Buildz = 0;
Resz = 0;

function Resource(name = "undefined", count= 0) {
  this.name = name;
  this.count= count;
}

function Building(name = "undefined", count= 0, cost= 0) {
  this.name = name;
  this.count= count;
  this.cost= cost;
}

function NewBuilding(name) {
  Builds[Buildz] = new Building(name);
  Buildz++;
}

function NewResource(name) {
  Res[Resz] = new Resource(name);
  Resz++;
}

NewBuilding("Test");
NewResource("Test2");

console.log(Builds);