如何使函数从作为参数传入的数组中获取多个变量?
Edited
例如:
实现这一目标:
const inputObj = [
['Anna', 10, 'Monday'],
['Anna', 15, 'Wednesday'],
['Beatrice', 8, 'Monday'],
['Beatrice', 11, 'Wednesday'],
['Anna', 4, 'Wednesday'],
['Beatrice', 5, 'Monday'],
['Beatrice', 16, 'Monday']
]
// expected output:
const outputObj = [
[ 'Anna', 10, 'Monday' ],
[ 'Anna', 19, 'Wednesday' ],
[ 'Beatrice', 29, 'Monday' ],
[ 'Beatrice', 11, 'Wednesday' ]
]
const arr = [0, 2]
const someFunction = (obj, v, a) => {
const result = obj.reduce((acc, cur) => {
const key = `${cur[a[0]]}|${cur[a[1]]}`
if(!acc[key]) acc[key] = cur
else acc[key][1] += cur[v]
return acc
}, {})
return Object.values(result)
}
console.log(someFunction(inputObj, 1, arr))
这样:
const arr = [0, 2, 3, ...] // basically the array could contain any number of items.
const someFunction = (obj, v, objParams) => {
const result = obj.reduce((acc, cur) => {
const key = ???
...
}, {})
}
为了使该函数可以重用并接受自定义大小的数组,请检查数组中的列号是否相同,然后将传入的列的总和作为 v
?
如何从 objParams 声明变量以获得与上面代码相同的结果?
另外如何在cur
中间添加v
?
最佳答案
假设 objParams 是一个未知大小的数组(本例中为字符串):
const objParams = ["c1", "c2", "c3"];
const key = objParams.join(']}|${cur[');
const built = '${cur[' + key + ']';
构建是:
${cur[c1]}|${cur[c2]}|${cur[c3]
关于javascript - make 函数从作为参数传入的数组中获取多个变量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50594713/