java - 如何使用参数化运行 JUnit SpringJUnit4ClassRunner？

Question

由于重复的@RunWith注解，以下代码无效:

@RunWith(SpringJUnit4ClassRunner.class)
@RunWith(Parameterized.class)
@SpringApplicationConfiguration(classes = {ApplicationConfigTest.class})
public class ServiceTest {
}

但是如何结合使用这两个注解呢？

Answer 1

您可以使用 SpringClassRule 和 SpringMethodRule - Spring 提供

import org.junit.ClassRule;
import org.junit.Rule;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.junit.runners.Parameterized;
import org.springframework.test.context.junit4.rules.SpringClassRule;
import org.springframework.test.context.junit4.rules.SpringMethodRule;

@RunWith(Parameterized.class)
@ContextConfiguration(...)
public class MyTest {

    @ClassRule
    public static final SpringClassRule SPRING_CLASS_RULE = new SpringClassRule();

    @Rule
    public final SpringMethodRule springMethodRule = new SpringMethodRule();

    ...