我正在使用下一个和上一个按钮,因此一次会显示一个问题,但是,一旦禁用下一个或上一个按钮,另一个按钮也不再起作用。这是我的代码:
var showing = [1, 0, 0, 0];
var questions = ['q0', 'q1', 'q2', 'q3'];
function next() {
var qElems = [];
for (var i = 0; i < questions.length; i++) {
qElems.push(document.getElementById(questions[i]));
}
for (var i = 0; i <= showing.length; i++) {
if (showing[i] == 1) {
showing[i] = 0;
if (i == showing.length - 1) {
document.getElementById("next").disabled = true;
} else {
console.log(i);
qElems[i + 1].style.display = 'block';
qElems[i].style.display = 'none';
showing[i + 1] = 1;
}
break;
}
}
}
function prev() {
var qElems = [];
for (var i = 0; i < questions.length; i++) {
qElems.push(document.getElementById(questions[i]));
}
for (var i = 0; i <= showing.length; i++) {
if (showing[i] == 1) {
showing[i] = 0;
if (i == showing.length - 4) {
document.getElementById("prev").disabled = true;
} else {
qElems[i - 1].style.display = 'block';
qElems[i].style.display = 'none';
showing[i - 1] = 1;
}
break;
}
}
}
最佳答案
我想你想要这个简化的脚本
我必须猜测 HTML,但只有一个函数。
window.addEventListener("load", function() {
let showing = 0;
const questions = document.querySelectorAll(".q");
questions[showing].style.display = "block";
const next = document.getElementById("next");
const prev = document.getElementById("prev");
document.getElementById("nav").addEventListener("click", function(e) {
var but = e.target, dir;
if (but.id === "prev") dir = -1;
else if (but.id === "next") dir = 1;
else return; // not a button
questions[showing].style.display = "none"; // hide current
showing += dir; // up or down
next.disabled = showing === questions.length-1;
if (showing <= 0) showing = 0;
prev.disabled = showing === 0
questions[showing].style.display = "block";
})
})
.q { display:none }
<div class="q" id="q0">Question 0</div>
<hr/>
<div class="q" id="q1">Question 1</div>
<hr/>
<div class="q" id="q2">Question 2</div>
<hr/>
<div class="q" id="q3">Question 3</div>
<hr/>
<div id="nav">
<button type="button" id="prev" disabled>Prev</button>
<button type="button" id="next">Next</button>
</div>
关于一旦按钮被禁用,JavaScript 就不会进一步执行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59391413/