javascript - 如何对具有多个值的对象数组进行分组？

Question

我想对我使用两个值office和reportName完成的对象数组进行分组，但我希望将电子邮件ID放在我收到的字符串中，但电子邮件ID不是唯一的。我必须尝试添加所有电子邮件但是当我尝试连接时它给出一个空字符串。谁能知道如何做到这一点

var data = [{
    email: 'amar045@gmail.com',
    office: 'xyz.in',
    reportName: 'payroll',
  },
  {
    email: 'amar0455@gmail.com',
    office: 'xyz.in',
    reportName: 'payroll',
  },
  {
    email: 'amar0455@gmail.com',
    office: 'xyz.in',
    reportName: 'payroll',
  },
  {
    email: 'amar045@gmail.com',
    office: 'xyz.in',
    reportName: 'payroll',
  },
  {
    email: 'amar0445@gmail.com',
    office: 'yyy.in',
    reportName: 'delievered',
  },
  {
    email: 'amar0445@gmail.com',
    office: 'yyy.in',
    reportName: 'delievered',
  },
  {
    email: 'amar0425@gmail.com',
    office: 'yyy.in',
    reportName: 'payroll',
  },

  {
    email: 'amar0425@gmail.com',
    office: 'xyz.in',
    reportName: 'delievered',
  }
];

let hash = Object.create(null);
let grouped = [];

data.forEach(function(o) {
  var key = ['office', 'reportName']
    .map(function(k) {
      return o[k];
    })
    .join('|');

  if (!hash[key]) {
    hash[key] = {
      office: o.office,
      reportName: o.reportName,
      email: ''
    };
    grouped.push(hash[key]);
  }
  ['email'].forEach(function(k) {
    hash[key][k] += o[k].split(',');
  });
});
console.log(grouped);

预期输出为

[
  {
    office: 'xyz.in',
    reportName: 'payroll',
     email: 'amar045@gmail.com, amar0455@gmail.com, amar0425@gmail.com'
  },
  {
    office: 'yyy.in',
    reportName: 'delievered',
    email: 'amar0445@gmail.com, amar0425@gmail.com'
  },
  {
    office: 'yyy.in',
    reportName: 'payroll',
    email: 'amar0425@gmail.com'
  }
]

Answer 1

您可以使用 String 的“includes”方法来检查电子邮件是否已存在并更新对象的电子邮件属性。

var data = [
  {
    email: 'amar045@gmail.com',
    office: 'xyz.in',
    reportName: 'payroll',
  },
  {
    email: 'amar0455@gmail.com',
    office: 'xyz.in',
    reportName: 'payroll',
  },
  {
    email: 'amar0455@gmail.com',
    office: 'xyz.in',
    reportName: 'payroll',
  },
  {
    email: 'amar045@gmail.com',
    office: 'xyz.in',
    reportName: 'payroll',
  },
  {
    email: 'amar0445@gmail.com',
    office: 'yyy.in',
    reportName: 'delievered',
  },
  {
    email: 'amar0445@gmail.com',
    office: 'yyy.in',
    reportName: 'delievered',
  },
  {
    email: 'amar0425@gmail.com',
    office: 'yyy.in',
    reportName: 'payroll',
  },

  {
    email: 'amar0425@gmail.com',
    office: 'xyz.in',
    reportName: 'delievered',
  }
];

let hash = Object.create(null);
let grouped = [];

data.forEach(function(o) {
  var key = ['office', 'reportName']
    .map(function(k) {
      return o[k];
    })
    .join('|');

  if (!hash[key]) {
    hash[key] = {office: o.office, reportName: o.reportName, email: ''};
    grouped.push(hash[key]);
  }
  ['email'].forEach(function(k) {
    if (hash[key] && !hash[key][k].includes(o[k])){
        hash[key][k] += o[k] + ',';
      }
    });
});
console.log(grouped);