php - 使用javascript输出html时出错

Question

我有这个 php 代码，我试图用它生成一个包含 html 文件内容的弹出窗口，但是在添加脚本标签后，没有显示 html。我尝试回显 $row2，但单词数组被打印到屏幕上，没有其他内容。

<?php
session_start();
if (isset($_GET["cmd"]))
  $cmd = $_GET["cmd"];
else
  die("You should have a 'cmd' parameter in your URL");
 $pk = $_GET["pk"];
$con = mysql_connect("localhost","root","geheim");
if(!$con)
{
die('Connection failed because of' .mysql_error());
}
mysql_select_db("ebay",$con);
if($cmd=="GetAuctionData")
{
$sql="SELECT * FROM Auctions WHERE ARTICLE_NO ='$pk'";
$sql2="SELECT ARTICLE_DESC FROM Auctions WHERE ARTICLE_NO ='$pk'";
$htmlset = mysql_query($sql2);
$row2 = mysql_fetch_array($htmlset);
echo $row2;
echo '<script> 
function makewindows(){
child1 = window.open ("about:blank");
child1.document.write('.$row2["ARTICLE_DESC"].');
child1.document.close(); 
}
</script>';

$result = mysql_query($sql);
while ($row = mysql_fetch_array($result))
{
echo "<div id='leftlayer'>
    <strong>Article Number</strong> ".$row['ARTICLE_NO']."
    <p><strong>Article Name</strong></p> ".$row['ARTICLE_NAME']."
    <p><strong>Subtitle</strong></p> ".$row['SUBTITLE']."
    <p><strong>Username</strong></p> ".$row['USERNAME']."
    <p><strong>Total Selling</strong></p> ".$row['QUANT_TOTAL']."
    <p><strong>Total Sold</strong></p> ".$row['QUANT_SOLD']."
    <p><strong>Category</strong></p> ".$row['CATEGORY']."
    <p><strong>Highest Bidder</strong></p> ".$row['BEST_BIDDER_ID']."
  </div>
<div class='leftlayer2'>
  <strong>Current Bid</strong> ".$row['CURRENT_BID']."
  <p><strong>Start Price</strong></p> ".$row['START_PRICE']."
  <p><strong>Buyitnow Price</strong></p> ".$row['BUYITNOW_PRICE']."
  <p><strong>Bid Count</strong></p> ".$row['BID_COUNT']."
  <p><strong>Start Date</strong></p> ".$row['ACCESSSTARTS']."
  <p><strong>End Date</strong></p> ".$row['ACCESSENDS']."
  <p><strong>Original End</strong></p> ".$row['ACCESSORIGIN_END']."
  <p><strong>Auction Type</strong></p> ".$row['AUCTION_TYPE']."
</div>
<div class='leftlayer2'>
    <strong>Private Auction</strong></p> ".$row['PRIVATE_AUCTION']."
  <p><strong>Paypal Accepted</strong></p> ".$row['PAYPAL_ACCEPT']."
  <p><strong>Auction Watched</strong></p> ".$row['WATCH']."
  <p><strong>Finished</strong></p> ".$row['FINISHED']."
  <p><strong>Country</strong></p> ".$row['COUNTRYCODE']."
  <p><strong>Location</strong></p> ".$row['LOCATION']."
  <p><strong>Conditions</strong></p> ".$row['CONDITIONS']."
</div>
<div class='leftlayer2'>
  <strong>Auction Revised</strong></p> ".$row['REVISED']."
  <p><strong>Cancelled</strong></p> ".$row['PRE_TERMINATED']."
  <p><strong>Shipping to</strong></p> ".$row['SHIPPING_TO']."
  <p><strong>Fee Insertion</strong></p> ".$row['FEE_INSERTION']."
  <p><strong>Fee Final</strong></p> ".$row['FEE_FINAL']."
  <p><strong>Fee Listing</strong></p> ".$row['FEE_LISTING']."
  <p><a href='#' onclick='makewindows(); return false;'>Click for full description </a></p>
</div>";

$lastImg = $row['PIC_URL'];
echo "<div id='rightlayer'>Picture Picture
<img src=".$lastImg.">
</div>";

}

}
mysql_close($con);
?>

编辑:我已经修复了 Roborg 指出的错误，但是脚本仍然无法加载并且不会给出精确的错误。

我已经更新了上面的代码

Answer 1

以及缺失的</script> ,

child1.document.write('.$row2["ARTICLE_DESC"].') 应该是

child1.document.write(' . json_encode($row2["ARTICLE_DESC"]) . ');

json_encode() 函数将为您处理任何引用。

编辑:

<a href='#' onclick=makewindows()>应该是<a href='#' onclick='makewindows(); return false;'> - 你应该在那里有引号，以及 return false当您点击链接时，将阻止您进入“#”。

此外，根据内存，我不确定您是否可以打开 about:blank 然后写入它 - 我认为它会将其视为跨域脚本。您最好在服务器上创建一个最小的“blank.html”文件并使用它。