javascript - 下面的脚本中缺少 ) 参数，有什么建议吗？为什么？

Question

    <form name="formone" id="optionsform">
    <fieldset>
    <label><input type="radio" name="group1" id="ac-yes" value="1">Yes</label>
    <label><input type="radio" name="group1" id="ac-no" value="0">No</label>

    <label><input type="radio" name="group2" id="bt-yes" value="2">Yes</label>
    <label><input type="radio" name="group2" id="bt-no" value="0">No</label>

    <a href="varible-address">CONTINUE</a>
    </fieldset>
    </form>
    <script>
    $(function(){
      var urls = new Array();
      urls[0]='http://myurl1/';// no + no
      urls[1]='http://myurl2/';// yes + no
      urls[2]='http://myurl3/';// no + yes
      urls[3]='http://myurl4/';// yes + yes

      $('input[type=radio]').click(fonction(){
        var score = 0;
        $('input[type=radio]:checked').each(function(){score+=parseInt($(this).val()});
        $('a').attr('href',urls[score]);
      }
   });
    </script>

Answer 1

改变

 $('input[type=radio]').click(fonction(){
    var score = 0;
    $('input[type=radio]:checked').each(function(){score+=parseInt($(this).val()});
    $('a').attr('href',urls[score]);
  }

至

  $('input[type=radio]').click(function(){ // 'function' not fonction
    var score = 0;
    $('input[type=radio]:checked').each(function(){score+=parseInt($(this).val()); /* missed ');' here */ });
    $('a').attr('href',urls[score]);
  }); // <-- see the closing ');' here