javascript - 在 ajax 成功回调中的 for 循环中，response[i] 未定义

Question

错误

TypeError: response[i] is undefined


    ...box' class='selectedSubjects' name='selectedSubjects' />
</td><td class='selected...

数组

[{"S_Code":"BCS-CER-IS","S_Name":"Information Systems.","C_Code":"BCS-CER","S_Status":"Active"},
{"S_Code":"BCS-CER-SD","S_Name":"Software Development.","C_Code":"BCS-CER","S_Status":"Active"},
{"S_Code":"BCS-CER-TEC","S_Name":"Computer & Network Technology","C_Code":"BCS-CER","S_Status":"Active"}]

AJAX成功回调

success: function (response) {
    var size = response.filter(function (value) {
        return value !== undefined
    }).length;
    for (var i = 0; i <= size; i++) {
        $("#subjectsTable tr:last").after("<tr class='success' data-index=" + (i + 1) + "><td><input type='checkbox' class='selectedSubjects' name='selectedSubjects' /></td><td class='selectedSCode'>" + response[i].S_Code + "</td><td class='selectedSName'>" + response[i].S_Name + "</td></tr>");

    }
}

为什么这个响应[i]未定义？

Answer 1

应该是 i < size因为数组索引来自 0至length-1

for (var i = 0; i < size; i++) {
    $("#subjectsTable tr:last").after("<tr class='success' data-index=" + (i + 1) + "><td><input type='checkbox' class='selectedSubjects' name='selectedSubjects' /></td><td class='selectedSCode'>" + response[i].S_Code + "</td><td class='selectedSName'>" + response[i].S_Name + "</td></tr>");

}

所以当 i == size response[i] 的值将是未定义的