javascript - jQuery Ajax 从 php 返回一些值

Question

我使用 ajax 从 php 文件中挑选错误，但遇到了一些麻烦。就像在 php 文件中一样，我将错误放入 $email_error 和 $password_error 中，因此我想将错误报告返回到 ajax 并将 $email_error 分配给 id = "email_errors"并将 $password_error 分配给 id = "password_errors"。也许有人可以解释我如何指定我想要返回哪些变量以及它应该采用什么id。我将在下面留下一些注释代码。谢谢!

php

<?php


if (isset($_POST['email']) && isset($_POST['password1']) && isset($_POST['password2'])) {

$email = trim ($_POST['email']);
$password1 = trim ($_POST['password1']);
$password2 = trim ($_POST['password2']);

}

$email_error = 'No errors<br>';
$password_error = 'No errors<br>';

if (empty($email))
$email_error = ('Pleas fill in email field<br>');

if ($email == 'example')
$email_error =('There already is user with this email<br>');

if (empty($password1))
$password_error =  ('Please fill in password fields<br>'); 

if (empty($password2))
$password_error = ('Please fill in password fields<br>');

$email_error; //this variable must be returned to ajax and assigned to id "email_errors"
$password_error; //this variable must be returned to ajax and assigned to id "password_errors"

?>

JavaScript

$(document).ready(function ()   {

$('#push_button').click(function() {

$.post('php.php',
{
email : $('#email').val(), // i take these variables to php
password1 : $('#password1').val(),
password1 : $('#password2').val()
} ,
function ( data ) { //what do i return here?

$('#email_errors').val(data); //how to assign $emaill_error to #email_errors
$('#password_errors').val(data); //how to assign $password_error to #password_errors

}
)
})


})

Answer 1

要返回值，只需使用 json_encode() 回显变量 例如

$return_array = new array();
$return_array['email_error'] = $email_error;
$return_array['password_errors'] = $password_errors;
echo json_encode($return_array);

在 JavaScript 函数(数据)中{}:

function ( data ) { //what do i return here?

    $('#email_errors').val(data['email_error']); //how to assign $emaill_error to #email_errors
    $('#password_errors').val(data['password_errors']); //how to assign $password_error to #password_errors

}