所以我有 2 个页面 top.php 和我的 Currentpage.php。首页有最新版本的Jquery和Bootstrap。当前页面有我还无法升级的代码。有没有办法在加载后停止 top.php Javascript 代码，然后加载 currentpage.php Javascript 代码？
top.php 有:
<html lang="en">
<head>
<!-- Bootstrap -->
<script src="../bootstrap/jquery/1.12.2/jquery.min.js"></script>
<!-- Bootstrap Core JavaScript -->
<script src="../bootstrap/js/bootstrap.min.js"></script>
</head>
<body>
<!-- some code here for top navigation -->
Currentpage.php 有这个:
<head>
<script type="style/js/jquery.form-2.47.js"></script>
<script type="text/javascript" src="style/js/jquery.ui.widget.js"></script>
<script type="text/javascript" src="style/js/jquery.ui.autocomplete.js"></script>
<script src="style/js/jquery-ui-1.8.1.dialog.min.js"></script>
<script type="text/javascript" src="index.js"></script>
</head>
<body>
<?php
include "../includes/top.php";
?>
<!-- stop the top.php code here then load the current page Javascript code -->
</body>
最佳答案
我使用一个变量来告诉 top.php 不要加载 jQuery。
top.php:
<html lang="en">
<head>
<?php if (!isset($jquery_loaded)) { ?>
<!-- Bootstrap -->
<script src="../bootstrap/jquery/1.12.2/jquery.min.js"></script>
<?php } ?>
<!-- Bootstrap Core JavaScript -->
<script src="../bootstrap/js/bootstrap.min.js"></script>
</head>
<body>
<!-- some code here for top navigation -->
当前页面.php:
<head>
<script type="style/js/jquery.form-2.47.js"></script>
<script type="text/javascript" src="style/js/jquery.ui.widget.js"></script>
<script type="text/javascript" src="style/js/jquery.ui.autocomplete.js"></script>
<script src="style/js/jquery-ui-1.8.1.dialog.min.js"></script>
<script type="text/javascript" src="index.js"></script>
</head>
<body>
<?php
$jquery_loaded = true;
include "../includes/top.php";
?>
<!-- stop the top.php code here then load the current page Javascript code -->
</body>
关于javascript - 如何阻止页面之间简单的 javascript 冲突？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/37618129/