假设我有以下 JSON:
{
"id": "foo",
"list": [
{
"id": "A",
"list": [
{
"id": "B",
"list": [
{
"id": "C",
"list": [
{
"id": "D",
"list": []
},
{
"id": "E",
"list": []
}
]
},
{
"id": "F",
"list": []
},
{
"id": "G",
"list": [
{
"id": "H",
"list": []
},
{
"id": "I",
"list": []
},
{
"id": "J",
"list": []
}
]
}
]
},
{
"id": "K",
"list": []
}
]
},
{
"id": "L",
"list": [
{
"id": "M",
"list": []
}
]
},
{
"id": "N",
"list": []
},
{
"id": "O",
"list": [
{
"id": "P",
"list": [
{
"id": "Q",
"list": []
},
{
"id": "R",
"list": []
},
{
"id": "S",
"list": []
},
{
"id": "T",
"list": [
{
"id": "U",
"list": []
}
]
},
{
"id": "V",
"list": [
{
"id": "W",
"list": [
{
"id": "X",
"list": []
},
{
"id": "Y",
"list": []
},
{
"id": "Z",
"list": []
}
]
}
]
}
]
}
]
}
]
}
我的问题是:如何计算每个子对象的数量并将该数字附加到每个对象的属性中?
示例:
- “C”对象在子对象内部和子对象上有 2 个对象:“D”和“E”。
- “W”对象在子对象内部和子对象上有 3 个对象:“X”、“Y”和“Z”。
- “V”对象在子对象内部和子对象上有(这里是窍门)4 个对象,“W”对象本身及其所有子对象(这 3 个对象)前面提到的)。
关于这一点,“C”对象应该有一个属性,我们将其命名为“allBelow”,包含数字2。“W”对象包含3,“V”对象包含4。依此类推,对于每个对象。
我想知道一些递归函数可以完成这项工作,但我没有实现它。
你能帮我一下吗?
最好的,
最佳答案
var myObj = {"id":"foo","list":[{"id":"A","list":[{"id":"B","list":[{"id":"C","list":[{"id":"D","list":[]},{"id":"E","list":[]}]},{"id":"F","list":[]},{"id":"G","list":[{"id":"H","list":[]},{"id":"I","list":[]},{"id":"J","list":[]}]}]},{"id":"K","list":[]}]},{"id":"L","list":[{"id":"M","list":[]}]},{"id":"N","list":[]},{"id":"O","list":[{"id":"P","list":[{"id":"Q","list":[]},{"id":"R","list":[]},{"id":"S","list":[]},{"id":"T","list":[{"id":"U","list":[]}]},{"id":"V","list":[{"id":"W","list":[{"id":"X","list":[]},{"id":"Y","list":[]},{"id":"Z","list":[]}]}]}]}]}]};
function count(obj) {
var c = obj.list.length;
c += obj.list.reduce((a, e) => a + count(e), 0);
obj.count = c; // assign the count after counting the subobjects.
return c; // return the count to be used by parent objects
}
count(myObj);
console.log(myObj);
关于Javascript - 计算 JSON 的所有嵌套对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41983595/