javascript - 检查对象数组中的属性并根据该值返回一个字符串

Question

我有一个像这样的对象数组，

   let employee =  [
            {
                NodeType: "intern",
                NodeName: "Node1"
            }, {
                NodeType: "intern",
                NodeName: "Node2"
            }, {
                NodeType: "full-time",
                NodeName: "Node1"
            }, {
                NodeType: "contract",
                NodeName: "Node1"
            }
 ]

我需要能够查看数组并查看是否所有员工都是全职员工，然后返回“全职”，或者员工列表是否只有“实习生”，返回实习生，或者如果是混合员工，则返回“混合”

我试过了

         var interntype = employee.find((obj) => {
                return obj.type == "intern" 
            });
         var fulltimetype = employee.find((obj) => {
                return obj.type == "full-time" 
            });
         var contracttype = employee.find((obj) => {
                return obj.type == "contract" 
            });

    if( internType) {
      return "intern";
    } else if (fulltimeType) {
          return "fullTime"
     } else return "mixed";

但有没有一种方法可以让我不多次执行此操作，而是执行一次

Answer 1

将所有 NodeType 值插入集合中，并检查大小。如果大于1，则返回混合项，如果不大于1，则返回单个项:

const employees = [{"NodeType":"intern","NodeName":"Node1"},{"NodeType":"intern","NodeName":"Node2"},{"NodeType":"full-time","NodeName":"Node1"},{"NodeType":"contract","NodeName":"Node1"}];

const getEmployeesType = (employees) => {
  const types = new Set(employees.map(({ NodeType }) => NodeType));
  return types.size > 1 ? 'mixed' : [...types][0];
};

console.log('mixed: ', getEmployeesType(employees));

console.log('internes: ', getEmployeesType(employees.slice(0, 2)));