java - 如何使用 Mongo Repository 查询同一个字段两次？

Question

所以我想进行查询以查找我的集合中存在的所有任务，条件是在两个给定日期之间具有日期属性。 我使用了 Between 关键字，但它不包括结果中的参数值。
例如，如果参数为 2019-09-20 和 2019-09-25，则不会在响应中返回为这些相同日期计划的任务。

我尝试使用 LessThanEqual 和 GreaterThanEqual，但出现以下错误:

org.springframework.data.mongodb.InvalidMongoDbApiUsageException: Due to limitations of the com.mongodb.BasicDocument, you can't add a second 'task.date' expression specified as 'task.date : Document{{$lte=Thu Sep 26 00:00:00 CEST 2019}}'. Criteria already contains 'task.date : Document{{$gte=Wed Sep 25 00:00:00 CEST 2019}}'.

这就是为什么我想知道是否有办法在同一字段上查询两次。

这是我的仓库。

public interface TaskRepository extends MongoRepository<TaskEntry, String> {
    List<TaskEntry> findByTask_DateGreaterThanEqualAndTask_DateLessThanEqual(Date dateFrom, Date dateTo);
}

谢谢。

更新:
这是我的收集、查询和使用 rustyx 的答案后的结果的示例。
这些是我的文件:

[
    {
        "id": "5c3da5b163c2789768d1402a",
        "code": "0000001",
        "createdDate": "2019-01-15T09:19:45.114+0000",
        "lastModifiedDate": "2019-01-15T09:19:45.114+0000",
        "task": {
            "codeRule": null,
            "title": "Task 1",
            "date": "2019-09-26T00:00:00.000+0000",
            "description": "This is the first task",
            "type": "UNITARY",
            "result": null
        }
    },
    {
        "id": "5c3da7dc63c2789768d1402b",
        "code": "0000002",
        "createdDate": "2019-01-15T09:29:00.125+0000",
        "lastModifiedDate": "2019-01-15T09:29:00.125+0000",
        "task": {
            "codeRule": null,
            "title": "Task 2",
            "date": "2019-09-26T00:00:00.000+0000",
            "description": "This is the second task",
            "type": "UNITARY",
            "result": null
        }
    },
    {
        "id": "5c3db0c763c27868b41e022b",
        "code": "0000003",
        "createdDate": "2019-01-15T10:07:03.693+0000",
        "lastModifiedDate": "2019-01-15T10:07:03.693+0000",
        "task": {
            "codeRule": null,
            "title": "Task 3",
            "date": "2019-09-28T00:00:00.000+0000",
            "description": "This is the third task",
            "type": "UNITARY",
            "result": null
        }
    }
]

这是我使用它得到的响应:

@Query("{'task.date': {$gte: ?0, $lte:?1 }}")
    List<TaskEntry> findByTask_DateBetween(Date dateFrom, Date dateTo);

还有这个:

/tasks?dateFrom=2019-09-26&dateTo=2019-09-28

响应:

[
    {
        "id": "5c3da5b163c2789768d1402a",
        "code": "0000001",
        "createdDate": "2019-01-15T09:19:45.114+0000",
        "lastModifiedDate": "2019-01-15T09:19:45.114+0000",
        "task": {
            "codeRule": null,
            "title": "Task 1",
            "date": "2019-09-26T00:00:00.000+0000",
            "description": "This is the first task",
            "type": "UNITARY",
            "result": null
        }
    },
    {
        "id": "5c3da7dc63c2789768d1402b",
        "code": "0000002",
        "createdDate": "2019-01-15T09:29:00.125+0000",
        "lastModifiedDate": "2019-01-15T09:29:00.125+0000",
        "task": {
            "codeRule": null,
            "title": "Task 2",
            "date": "2019-09-26T00:00:00.000+0000",
            "description": "This is the second task",
            "type": "UNITARY",
            "result": null
        }
    }
]

日期为 2019-09-26 的任务正在添加到响应中，这意味着 $gte: ?0 正在运行，但日期为 2019-09-28 的任务不在那里。

Answer 1

您可以使用“之间”:

    List<TaskEntry> findByTask_DateBetween(Date dateFrom, Date dateTo);

如果这还不够，请使用自定义查询:

    @Query("{'date': {$gte: ?0, $lte:?1 }}")
    List<TaskEntry> findByTask_DateBetween(Date dateFrom, Date dateTo);