下面代码的目的是使用Ajax重复获取PHP查询结果,直到结果为“6”。
当我的CPU风扇开始大声咆哮,并且几秒钟后,“正在加载...”消息开始闪烁时,接收到“6”的结果后,脚本继续运行,这是正常的.
想法?
function refreshData(){
var display = document.getElementById("content");
var xmlhttp = new XMLHttpRequest();
xmlhttp.open("GET", "get_status.php");
//xmlhttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xmlhttp.send();
xmlhttp.onreadystatechange = function() {
if (this.readyState === 4 && this.status === 200) {
display.innerHTML = this.responseText;
var test_response = this.responseText;
} else {
display.innerHTML = "Loading...";
};
if (this.responseText != "6") {
refreshData();
}
}
}
这是 PHP 代码:
<?php
$dbconn = pg_connect("host=localhost dbname=postgres user=postgres password=kevin234") or die('Could not connect: ' . pg_last_error());
set_time_limit(0);
$result = pg_query('select max(num_files), max(file_num) from status');
$num_files = pg_fetch_row($result);
echo "max_file_num = " . $num_files[1];
?>
从这段代码中调用refreshData():
var upload = function(files) {
var formData = new FormData(),
xhr = new XMLHttpRequest(),
x;
xhr.upload.addEventListener("progress", progressHandler, false);
//xhr.addEventListener("load", refreshData, false);
//xhr.addEventListener("error", errorHandler, false);
//xhr.addEventListener("abort", abortHandler, false);
for(x = 0; x < files.length; x = x +1) {
formData.append('file[]', files[x]);
}
xhr.onload = function() {
var data = JSON.parse(this.responseText);
displayUploads(data);
}
xhr.open('post', 'ids_v0.00_progress_bar.php');
xhr.send(formData);
function progressHandler (event) {
document.getElementById("loaded_n_total").innerHTML = "Uploaded "+event.loaded+" bytes of "+event.total;
var percent = (event.loaded / event.total) * 100;
if (event.loaded = event.total) {
refreshData();
}
}
}
最佳答案
It is working accept that the script continues to run after the result of "6"
您需要将函数的重新调用移至 xmlhttp
调用的 onreadystatechange
成功中。这样,一次发送一个请求,而不是数百个。
function refreshData() {
var display = document.getElementById("content");
var xmlhttp = new XMLHttpRequest();
xmlhttp.open("GET", "get_status.php");
//xmlhttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xmlhttp.send();
xmlhttp.onreadystatechange = function() {
if (this.readyState === 4 && this.status === 200) {
display.innerHTML = this.responseText;
var test_response = this.responseText;
if (this.responseText != "6") {
refreshData();
}
} else {
display.innerHTML = "Loading...";
};
}
}
为什么改变
您的代码存在的问题是,无论 responseText
值如何,您的网站都会继续侧面发送请求。 responseText != "6"
所做的唯一事情是检查该请求实例是否应该发送另一个请求。当一个请求完成时,必须有条件地重新发送请求,即在 if(this.readyState === 4 && this.status === 200)
中。
关于javascript - XMLHttpRequest() 无限循环,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50201246/