javascript - 等待功能但仍然没有结果

Question

我正在尝试创建两个函数，一个函数需要两周，另一个函数创建一个提示，我想在其中显示几周，这就是我尝试过的:

let weeks = {};

async function getWeeks() {
    await sql.open('./weeks.db');
    sql.get(`SELECT * FROM weeks WHERE id = "1"`).then(row => {
        weeks.firstWeek = row.week;
    }).catch(console.error);
    sql.get(`SELECT * FROM weeks WHERE id = "2"`).then(row => {
        weeks.secondWeek = row.week;
    }).catch(console.error);
    sql.close();
}

await getWeeks().then(async function() {
    makeEdits();
});

async function makeEdits() {
    message.channel.send(new Discord.RichEmbed().setTitle(`Which week do you want?`).setDescription(`🇪 for **${weeks.firstWeek}**.\n🇹 for **${weeks.secondWeek}**.`)).then(async function(message) {
        // Both values are undefined here however I can use them deeper down into the function

我尝试等待一个函数，然后启动另一个函数，但它没有按预期工作，我应该做什么？

Answer 1

你还必须await sql.get调用，您可以重构您的 .then发送至await提高可读性:

 async function getWeeks() {
   const weeks = {}; // local scope helps to prevent racing errors

   await sql.open('./weeks.db');

   try {
     const row = await sql.get(`SELECT * FROM weeks WHERE id = "1"`);
     weeks.firstWeek = row.week;
   } catch(error) { console.error(error); }

   try {
     const row = await sql.get(`SELECT * FROM weeks WHERE id = "2"`);  
     weeks.secondWeek = row.week;
   } catch(error) { console.error(error); }

   sql.close();

   return weeks;
}

function makeEdits(weeks) { /*...*/ }

makeEdits(await getWeeks());