javascript - 数组排序有两个要求

Question

我已经解决了对数组进行排序的麻烦，该数组应该按接下来的两个要求进行排序:

1. true 上要求的属性应该首先列出。
2. 然后按字母顺序

我已经这样做了，它有效，但我感觉有一个聪明的方法......:-|

const originalAttributes = [{
    name: "P",
    required: false
  },
  {
    name: "D",
    required: true
  },
  {
    name: "W",
    required: true
  },
  {
    name: "A",
    required: true
  },
  {
    name: "N",
    required: false
  },
  {
    name: "S",
    required: false
  }
];

function listNames(originalAttributes) {
  originalAttributes.forEach(item => {
    console.log(`${item.name} ${item.required ? '--R' : ''}`);
  })
}

listNames(originalAttributes)

console.log('------------------------------');

const sortedAttributes = originalAttributes.sort((a, b) => {
  if (a.required && b.required) {
    return a.name < b.name ? -1 : 1;
  } else if (a.required) {
    return -1
  } else if (!b.required) {
    return a.name < b.name ? -1 : 1;
  }
});

listNames(sortedAttributes)

有什么建议吗？

Answer 1

您可以像下一个示例一样进行处理。

说明:一元加用于将 bool 值转换为数字，如果这些 bool 值的差值是零，然后使用 name 字段与 localeCompare() 进行比较.

const originalAttributes = [
    {name: "P", required: false},
    {name: "D", required: true},
    {name: "W", required: true},
    {name: "A", required: true},
    {name: "N", required: false},
    {name: "S", required: false},
    {name: "SI", required: false}
];

let res = originalAttributes.sort((a, b) =>
    (+b.required - +a.required) || a.name.localeCompare(b.name)
);

const listNames = a => a.map(
    i => `${i.name} ${i.required ? '--R' : ''}`
).join("\n");

console.log(listNames(res));