javascript - 两个对象数组的 typescript 差异

Question

我有两个对象数组，想要找到第二个数组中缺少但属于第一个数组的一部分的项目，基本上是 array1-array2。我尝试使用过滤器，但无法获得所需的结果。请帮忙。提前致谢。

这是代码:

 testData=[
       {id: 0, name: "policy001"},
       {id: 2, name: "policy002"}];
       sourceData= [
          {id: 0, name: "policy001"},
          {id: 2, name: "policy002"},
          {id: 3, name: "policy003"},
          {id: 4, name: "policy004"},
          {id: 5, name: "policy005"}, 
      ];

      let missing = sourceData.filter(item =>  testData.indexOf(item) < 0);
      console.log("Miss")
      console.log(missing )//Returns the sourceData instead of diff.

Answer 1

尝试findIndex() :

The findIndex() method returns the index of the first element in the array that satisfies the provided testing function. Otherwise, it returns -1, indicating that no element passed the test.

testData = [{
        id: 0,
        name: "policy001"
    },
    {
        id: 2,
        name: "policy002"
    }
];
sourceData = [{
        id: 0,
        name: "policy001"
    },
    {
        id: 2,
        name: "policy002"
    },
    {
        id: 3,
        name: "policy003"
    },
    {
        id: 4,
        name: "policy004"
    },
    {
        id: 5,
        name: "policy005"
    },
];

console.log(sourceData.filter(item => testData.findIndex(x => x.id == item.id) < 0))