我有以下文档结构:
{
"country_id" : 328,
"country_name" : "Australien",
"cities" : [{
"city_id" : 19398,
"city_name" : "Bondi Beach (Sydney)"
}, {
"city_id" : 31102,
"city_name" : "Double Bay (Sydney)"
}, {
"city_id" : 31101,
"city_name" : "Rushcutters Bay (Sydney)"
}, {
"city_id" : 817,
"city_name" : "Sydney"
}, {
"city_id" : 31022,
"city_name" : "Wolly Creek (Sydney)"
}, {
"city_id" : 18851,
"city_name" : "Woollahra"
}],
"regions" : {
"region_id" : 796,
"region_name" : "Australien: New South Wales (Sydney)"
}
}
对于分面导航,我想计算属性country_id、cities.city_id、regions_region_id,我想我可以使用map/reduce 来做到这一点。
对于给定的结构这可能吗?
也许有人可以指出我正确的 map /减少方向。
最佳答案
Mongo map-reduce 示例可以在这里找到:http://docs.mongodb.org/manual/tutorial/map-reduce-examples/
每个唯一的country_id、city_id和region_id元组的文档数量很简单:
> function m() {
for(var i in this.cities) {
emit({country_id:this.country_id,
city_id:this.cities[i].city_id,
region_id:this.regions.region_id},
1);
} }
> function r(id,docs) {
return Array.sum(docs);
}
> db.loc.mapReduce(m,r,{out:"map_reduce_out"})
{
"result" : "map_reduce_out",
"timeMillis" : 5,
"counts" : {
"input" : 1,
"emit" : 6,
"reduce" : 0,
"output" : 6
},
"ok" : 1,
}
> db.map_reduce_out.find()
{ "_id" : { "country_id" : 328, "city_id" : 817, "region_id" : 796 }, "value" : 1 }
{ "_id" : { "country_id" : 328, "city_id" : 18851, "region_id" : 796 }, "value" : 1 }
{ "_id" : { "country_id" : 328, "city_id" : 19398, "region_id" : 796 }, "value" : 1 }
{ "_id" : { "country_id" : 328, "city_id" : 31022, "region_id" : 796 }, "value" : 1 }
{ "_id" : { "country_id" : 328, "city_id" : 31101, "region_id" : 796 }, "value" : 1 }
{ "_id" : { "country_id" : 328, "city_id" : 31102, "region_id" : 796 }, "value" : 1 }
关于mongodb - 在嵌套文档上使用 mongo 进行 MapReduce,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16319283/