javascript - 使用 array.find() 在 javascript 数组中查找元素

Question

如何使用 find 在 javascript 数组中搜索元素？

 const array = [{
    "key1": "val1",
    "key2": "val2",
    "key3": "val3",
    "key4": "val4",
    "key5": "val5",
},
{
    "key1": "val6",
    "key2": "val7",
    "key3": "val8",
    "key4": "val9",
    "key5": "val10"
}]

我想搜索值searchvalue。我假设它将匹配 val1，如果是这样，我想获得 key5:

array.find((element) => element.key1 === searchvalue).k​​ey5)

但是如果没有匹配的element.key1 === searchvalue，那么我想搜索key2并找到结果的key6:

array.find((element) => element.key2 === searchvalue).k​​ey5)

到目前为止我所做的是:

var arrayElement = array.find((element) => element.key1 === 
    searchvalue)
const value =  (arrayElement !== undefined ) ? arrayElement.key5: array.find((element) => element.key2 === 
    searchvalue).key6;

Answer 1

您可以链接查找对象并从中获取值的尝试。

var array = [{ key1: "val1", key2: "val2", key3: "val3", key4: "val4", key5: "val5" }, { key1: "val6", key2: "val7", key3: "val8", key4: "val9", key5: "val10" }],
    searchvalue = "val7",
    result = 
        (array.find(o => o.key1 === searchvalue) || {}).key5 ||
        (array.find(o => o.key2 === searchvalue) || {}).key4;

console.log(result);