javascript - 有没有办法让js逐行执行这个脚本

Question

我正在尝试制作一个脚本，每次创建新的 React 应用程序时都可以自动化我的项目，因此首先我制作了一个运行 main.js 脚本的 bat 文件

这是bat文件

@echo off
setlocal enableextensions

REM run my main
node "C:\Windows\System32\automate\main.js" %1

这是 main.js 文件

const { exec } = require("child_process");
const { replace, rename } = require("./file.js");
const axios = require("axios").default;

let state = {
  cwd: "E:/WORK/Projects",
  token: "[[my github token]]",
  project: {
    name: process.argv[2],
    path: "E:/WORK/Projects/" + process.argv[2],
    src: "E:/WORK/Projects/" + process.argv[2] + "/src",
  },
};

// init
let { cwd, project, token } = state;

//
//
// main
// create the app
exec("create-react-app " + project.name, { cwd });

// install debs
exec("npm i node-sass", { cwd: project.path });

// use sass
rename(project.src + "/index.css", "index.scss");
rename(project.src + "/App.css", "App.scss");
replace(project.src + "/index.js", "./index.css", "./index.scss");
replace(project.src + "/App.js", "./App.css", "./App.scss");

// structure my app
let code = [
  'mkdir "' + project.src + '/App"',
  'mkdir "' + project.src + '/App/Elements"',
  'mkdir "' + project.src + '/App/nav"',
  'touch "' + project.src + '/App/nav.jsx"',
  'touch "' + project.src + '/App/nav/nav.scss"',
];
code = code.join(" && ");
exec(code);

// push to github
axios({
  method: "post",
  url: "https://api.github.com/user/repos?access_token=" + token,
  data: {
    name: project.name,
  },
})
  .then((res) => {
    let repo = res.data.clone_url;
    let c = [
      "git remote add origin " + repo,
      "git push --set-upstream origin master",
      "git push",
    ].join(" && ");
    exec(c);
  })
  .catch((err) => {
    console.log(err.response.data.errors);
  });

// open in code
exec("code " + project.path);

// final message
console.log("Have Fun!");

现在一切都准备好了，但我唯一的问题是每行都异步执行
例如 create-react-app 命令，这需要很多时间，并且接下来的每一行都依赖于它来首先完成

Answer 1

您可以使用execSync代替exec:

const {execSync} = require('child_process');

以下是有关此功能的主要文档:NodeJs Docs

具体说明:

The child_process.execSync() method is generally identical to child_process.exec() with the exception that the method will not return until the child process has fully closed. When a timeout has been encountered and killSignal is sent, the method won't return until the process has completely exited. If the child process intercepts and handles the SIGTERM signal and doesn't exit, the parent process will wait until the child process has exited.