我正在尝试获取 json 数据,但无法这样做。我正在尝试获取特定城市的天气数据。这是我的 json 数据
{
"data":
{
"current_condition":
[
{
"cloudcover": "100",
"humidity": "100",
"observation_time": "01:07 PM",
"precipMM": "0.2",
"pressure": "993",
"temp_C": "-6",
"temp_F": "21",
"visibility": "10",
"weatherCode": "368",
"weatherDesc":
[
{
"value": "Light snow showers"
}
],
"weatherIconUrl":
[
{
"value": "http:\/\/www.worldweatheronline.com\/images\/wsymbols01_png_64\/wsymbol_0027_light_snow_showers_night.png"
}
],
"winddir16Point": "N",
"winddirDegree": "360",
"windspeedKmph": "9",
"windspeedMiles": "6"
}
],
"request":
[
{
"query": "Tampere, Finland",
"type": "City"
}
],
"weather":
[
{
"date": "2012-01-07",
"precipMM": "2.3",
"tempMaxC": "-4",
"tempMaxF": "25",
"tempMinC": "-8",
"tempMinF": "17",
"weatherCode": "326",
"weatherDesc":
[
{
"value": "Light snow"
}
],
"weatherIconUrl":
[
{
"value": "http:\/\/www.worldweatheronline.com\/images\/wsymbols01_png_64\/wsymbol_0011_light_snow_showers.png"
}
],
"winddir16Point": "NNW",
"winddirDegree": "336",
"winddirection": "NNW",
"windspeedKmph": "9",
"windspeedMiles": "5"
},
{
"date":
"2012-01-08",
"precipMM": "0.0",
"tempMaxC": "-7",
"tempMaxF": "19",
"tempMinC": "-9",
"tempMinF": "17",
"weatherCode": "116",
"weatherDesc":
[
{
"value": "Partly Cloudy"
}
],
"weatherIconUrl":
[
{
"value": "http:\/\/www.worldweatheronline.com\/images\/wsymbols01_png_64\/wsymbol_0002_sunny_intervals.png"
}
],
"winddir16Point": "SSE",
"winddirDegree": "148",
"winddirection": "SSE",
"windspeedKmph": "5",
"windspeedMiles": "3"
}
]
}
}
这是我尝试使用 jquery 获取它的方法
var container = $('.weatherContainer');
var url = 'http://free.worldweatheronline.com/feed/weather.ashx?q=Tampere&format=json&num_of_days=2&key=a84523bbed133415120701&callback=?';
$.getJSON(url, function(w) {
//console.log(w.data);
var contents = "<div class='c'>";
$.each(w.data, function(i, res){
//alert('h');
$.each(res.weather, function(j,action) {
//alert('i');
contents += "<section>" + action.tempMaxC + "</section>";
});
});
contents += "</div>";
container.append(contents);
});
请帮忙。我怎样才能实现它?上面的代码对我不起作用。
错误是什么
object is undefined
length = object.length, jquery-latest.js (line 630)
我想获取天气对象内的数据。我怎样才能得到它?
好的,这是我取消注释 console.log enter link description here 时的输出图像
最佳答案
您的问题是嵌套的“each”循环。您告诉 jQuery 响应的 data
对象中的每个对象,找到其中的每个 weather
对象并对其进行迭代。只有一个 weather
对象,并且它直接位于 data
内部,因此请删除外部循环并使用此单个循环进行简化:
$.each(w.data.weather, function(i, res) {
contents += "<section>" + res.tempMaxC + "</section>";
});
总而言之,你已经非常接近了。这是a working fiddle of your code随着微小的变化。
关于javascript - 无法检索 json 数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8770666/