我正在使用 MongoDB 为 SPA (Angular) 构建 python 后端。
这是我使用的:Python 3.4
、MongoDB 3
、Flask
、flask-mongoengine
和 flask-restful
现在我从后端收到以下 JSON:
[
{
"_id": {
"$oid": "55c737029380f82fbf52eec3"
},
"created_at": {
"$date": 1439129906376
},
"desc": "Description.....",
"title": "This is title"
},
etc...
]
我想收到类似的东西:
[
{
"_id": "55c737029380f82fbf52eec3",
"created_at": 1439129906376,
"desc": "Description.....",
"title": "This is title"
},
etc...
]
我现在的代码:
from flask import json
from vinnie import app
from flask_restful import Resource, Api
from vinnie.models.movie import Movie
api = Api(app)
class Movies(Resource):
def get(self):
movies = json.loads(Movie.objects().all().to_json())
return movies
api.add_resource(Movies, '/movies')
型号:
import datetime
from vinnie import db
class Movie(db.Document):
created_at = db.DateTimeField(default=datetime.datetime.now, required=True)
title = db.StringField(max_length=255, required=True)
desc = db.StringField(required=True)
def __unicode__(self):
return self.title
为前端格式化方便的 JSON 的最佳方式是什么?
最佳答案
如果您有信心摆脱所有类似情况,那么您当然可以编写与该模式匹配的代码。例如:
info = [
{
"_id": {
"$oid": "55c737029380f82fbf52eec3"
},
"created_at": {
"$date": 1439129906376
},
"desc": "Description.....",
"title": "This is title"
},
#etc...
]
def fix_array(info):
''' Change out dict items in the following case:
- dict value is another dict
- the sub-dictionary only has one entry
- the key in the subdictionary starts with '$'
In this specific case, one level of indirection
is removed, and the dict value is replaced with
the sub-dict value.
'''
for item in info:
for key, value in item.items():
if not isinstance(value, dict) or len(value) != 1:
continue
(subkey, subvalue), = value.items()
if not subkey.startswith('$'):
continue
item[key] = subvalue
fix_array(info)
print(info)
这将返回:
[{'title': 'This is title', 'created_at': 1439129906376, 'desc': 'Description.....', '_id': '55c737029380f82fbf52eec3'}]
显然,用 JSON 重新格式化是微不足道的。
关于json - 摆脱 JSON 中的 Mongo $ 符号,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31904012/