这是我在尝试运行 JSON.parse 之前返回的 JSON.stringify
{"id":"2","name":"<small>L</small>(+)-Amethopterin Hydrate","class":"6.1","subclass":"","packing_group":"III","un":"2811","cas":"133073-73-1","poisons":"","hazardous":"Yes","restricted":"No","epa":"","added_by":"0","carcinogen":null},
{"id":"3","name":"(+)-Biotin 4-Nitrophenyl ester","class":"","subclass":"","packing_group":"","un":"","cas":"33755-53-2","poisons":"","hazardous":"No","restricted":"No","epa":"","added_by":"0","carcinogen":null},
{"id":"4","name":"(+)-Biotin N-hydroxysuccinimide ester","class":"","subclass":"","packing_group":"","un":"","cas":"35013-72-0","poisons":"","hazardous":"No","restricted":"No","epa":"","added_by":"0","carcinogen":null}
当我尝试 JSON.parse 时，我得到Unexpected end of JSON input。我无法将其作为 JSON 对象进行访问，因为它会显示 can't Define id 或某种程度的内容。
JSON.parse(this.searchService.searchJson(this.php_url));
this.searchService.searchJson(this.php_url) 基本上就是我的 JSON 字符串。给出如上所述的错误。
此外，如果我只是尝试对 3 个元素中的 1 个进行字符串化，它会给我 JSON 中位置 0 处的意外标记 u
调用函数:
searchJson(url: any): any
{
let items: any = [];
let new_data: any = [];
$.getJSON(url ,
function(data)
{
let temp_items: any = {};
console.log(data);
$.each(data, function (key, val)
{
new_data.push(JSON.stringify(val));
});
});
return new_data;
}
最佳答案
你必须用[]包裹它，因为那是一个对象数组:
const data = [{"id":"2","name":"<small>L</small>(+)-Amethopterin Hydrate","class":"6.1","subclass":"","packing_group":"III","un":"2811","cas":"133073-73-1","poisons":"","hazardous":"Yes","restricted":"No","epa":"","added_by":"0","carcinogen":null}, {"id":"3","name":"(+)-Biotin 4-Nitrophenyl ester","class":"","subclass":"","packing_group":"","un":"","cas":"33755-53-2","poisons":"","hazardous":"No","restricted":"No","epa":"","added_by":"0","carcinogen":null}, {"id":"4","name":"(+)-Biotin N-hydroxysuccinimide ester","class":"","subclass":"","packing_group":"","un":"","cas":"35013-72-0","poisons":"","hazardous":"No","restricted":"No","epa":"","added_by":"0","carcinogen":null}]
console.log(data); 将返回 [Object, Object, Object]
或者如果您想作为 JSON 字符串进行处理，您应该这样做:
const data = '[{"id":"2","name":"<small>L</small>(+)-Amethopterin Hydrate","class":"6.1","subclass":"","packing_group":"III","un":"2811","cas":"133073-73-1","poisons":"","hazardous":"Yes","restricted":"No","epa":"","added_by":"0","carcinogen":null}, {"id":"3","name":"(+)-Biotin 4-Nitrophenyl ester","class":"","subclass":"","packing_group":"","un":"","cas":"33755-53-2","poisons":"","hazardous":"No","restricted":"No","epa":"","added_by":"0","carcinogen":null}, {"id":"4","name":"(+)-Biotin N-hydroxysuccinimide ester","class":"","subclass":"","packing_group":"","un":"","cas":"35013-72-0","poisons":"","hazardous":"No","restricted":"No","epa":"","added_by":"0","carcinogen":null}]'
JSON.parse(data) 也会返回 [Object, Object, Object]
关于javascript - JSON.parse 返回错误，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/41052941/