javascript - 按索引删除 javascript 键/值对

Question

function removeString(obj) {
  var propertyArray = Object.values(obj);            //make array of just properties 
  for(var i = 0; i < propertyArray.length; i++) {
     if (typeof propertyArray[i] === "string")          //find string
     delete Object.keys(obj)[i];  //delete the key with the same index as the string
  }                                
  return obj;//return new object without string 
}

var testObject = {size: 6, name: 'String', age: 20}

console.log(removeString(testObject)) //I want {size: 6, age: 20}

我想要上面的函数删除值为string的字段，而不是返回原始对象。

对于任何阅读本文/愿意提供帮助的人，提前致谢!

Answer 1

你需要做:

delete obj[Object.keys(obj)[i]] 

除了删除Object.keys(obj)[i]。现在，您只需删除检索到的值 name，而不是 obj 的属性 name，即 obj["name"]。这就是为什么它从未从 obj 中删除的原因。这是一个片段示例:

function removeString(obj) {

var propertyArray = Object.values(obj);            
for(var i = 0; i < propertyArray.length; i++)      
if (typeof propertyArray[i] === "string")   
  delete obj[Object.keys(obj)[i]]                                 
return obj;                                                                                       
}



var testObject = {size: 6, name: 'String', age: 20}

console.log(removeString(testObject))