我需要循环访问以下对象并为每个子对象运行一个函数。基本上我想从对象生成 HTML,因此对象内的子对象显然将是 HTML 内的子对象。
所以,对象:
var html = {
'div' : {
'id': 'marvLightbox__container',
0: {
'div': {
'class': 'marvLightbox__left',
'event_click': 'left'
}
},
1: {
'div': {
'class': 'marvLightbox__right',
'event_click': 'right'
}
},
2: {
'div': {
'class': 'marvLightbox',
0: {
'div': {
'class': 'marvLightbox__eschint',
'content': 'Press <span>ESC</span> to close'
},
'div': {
'class': 'marvLightbox__close',
'event_click': 'close'
},
'img': {
'src': '/img-src/_themev2-knightsbridgecars-1544/making-of/making-004.jpg',
'class': 'responsive-img'
}
}
}
}
}
}
如果我们暂时忽略 event_click
部分,上面的对象应该生成以下内容:
<div id="marvLightbox__container">
<div class="marvLightbox__left"></div>
<div class="marvLightbox__right"></div>
<div class="marvLightbox">
<div class="marvLightbox__eschint">
Press <span>ESC</span> to close
</div>
<div class="marvLightbox__close"></div>
<img src="/img-src/_themev2-knightsbridgecars-1544/making-of/making-004.jpg" alt="" class="responsive-img">
</div>
</div>
这是我当前拥有的代码,但是它没有深入到对象中并且输出不正确。
Object.size = function(obj) {
var size = 0, key;
for (key in obj) {
if (obj.hasOwnProperty(key)) size++;
}
return size;
};
function allDescendants (node, n) {
var i = 0;
for (var property in node) {
var child = node[property];
console.log(property);
if (Object.size(child) > 1) {
allDescendants(child, i);
}
i++;
//allDescendants(child, i);
doSomethingToNode(child, i);
}
}
function doSomethingToNode(node, n) {
console.log(n + ': ' + node);
}
allDescendants(html);
这是上面代码当前输出的内容,我也会在下面放一个 Codepen,以便您可以更轻松地测试:
marv.lightbox.js:141 div
marv.lightbox.js:141 0
marv.lightbox.js:151 1
marv.lightbox.js:152 Object {div: Object}
marv.lightbox.js:141 1
marv.lightbox.js:151 2
marv.lightbox.js:152 Object {div: Object}
marv.lightbox.js:141 2
marv.lightbox.js:151 3
marv.lightbox.js:152 Object {div: Object}
marv.lightbox.js:141 id
marv.lightbox.js:141 0
marv.lightbox.js:151 1
marv.lightbox.js:152 m
marv.lightbox.js:141 1
marv.lightbox.js:151 2
marv.lightbox.js:152 a
marv.lightbox.js:141 2
marv.lightbox.js:151 3
marv.lightbox.js:152 r
marv.lightbox.js:141 3
marv.lightbox.js:151 4
marv.lightbox.js:152 v
marv.lightbox.js:141 4
marv.lightbox.js:151 5
marv.lightbox.js:152 L
marv.lightbox.js:141 5
marv.lightbox.js:151 6
marv.lightbox.js:152 i
marv.lightbox.js:141 6
marv.lightbox.js:151 7
marv.lightbox.js:152 g
marv.lightbox.js:141 7
marv.lightbox.js:151 8
marv.lightbox.js:152 h
marv.lightbox.js:141 8
marv.lightbox.js:151 9
marv.lightbox.js:152 t
marv.lightbox.js:141 9
marv.lightbox.js:151 10
marv.lightbox.js:152 b
marv.lightbox.js:141 10
marv.lightbox.js:151 11
marv.lightbox.js:152 o
marv.lightbox.js:141 11
marv.lightbox.js:151 12
marv.lightbox.js:152 x
marv.lightbox.js:141 12
marv.lightbox.js:151 13
marv.lightbox.js:152 _
marv.lightbox.js:141 13
marv.lightbox.js:151 14
marv.lightbox.js:152 _
marv.lightbox.js:141 14
marv.lightbox.js:151 15
marv.lightbox.js:152 c
marv.lightbox.js:141 15
marv.lightbox.js:151 16
marv.lightbox.js:152 o
marv.lightbox.js:141 16
marv.lightbox.js:151 17
marv.lightbox.js:152 n
marv.lightbox.js:141 17
marv.lightbox.js:151 18
marv.lightbox.js:152 t
marv.lightbox.js:141 18
marv.lightbox.js:151 19
marv.lightbox.js:152 a
marv.lightbox.js:141 19
marv.lightbox.js:151 20
marv.lightbox.js:152 i
marv.lightbox.js:141 20
marv.lightbox.js:151 21
marv.lightbox.js:152 n
marv.lightbox.js:141 21
marv.lightbox.js:151 22
marv.lightbox.js:152 e
marv.lightbox.js:141 22
marv.lightbox.js:151 23
marv.lightbox.js:152 r
marv.lightbox.js:151 4
marv.lightbox.js:152 marvLightbox__container
marv.lightbox.js:151 1
marv.lightbox.js:152 Object {0: Object, 1: Object, 2: Object, id: "marvLightbox__container"}
最佳答案
首先,我会考虑重组您的数据以利用数组,这将使遍历变得更加容易。
var html = {
'id': 'marvLightbox__container',
'children' : [
{
'class': 'marvLightbox__left',
'event_click': 'left'
},
{
'class': 'marvLightbox__right',
'event_click': 'right'
},
{
'class': 'marvLightbox',
'children': [
{
'class': 'marvLightbox__eschint',
'content': 'Press <span>ESC</span> to close'
},
{
'class': 'marvLightbox__close',
'event_click': 'close'
},
{
'src': '/img-src/_themev2-knightsbridgecars-1544/making-of/making-004.jpg',
'class': 'responsive-img'
}
]
}
]
}
然后你可以像这样遍历整个对象:
//Recursively loop through all children
function walkTheObject(dataNode, func) {
func(dataNode);
if(dataNode.children) {
dataNode.children.forEach((child) => {
walkTheObject(child, func)
})
}
}
关于javascript - 循环遍历对象和未知数量的子对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44549580/