javascript - 如何根据2个键获取不同的数组列表？

Question

我有以下 2 个数组。

const array1 = [
    {name: "V1", year: "2018", isDefault: false},
    {name: "V2", year: "2018", isDefault: false},
    {name: "V3", year: "2018", isDefault: false},
    {name: "V4", year: "2018", isDefault: false},
    {name: "V1", year: "2019", isDefault: true}
  ];

和

const array2 = [
    {name: "V1", year: "2018", isDefault: false},
    {name: "V2", year: "2018", isDefault: false},
    {name: "V3", year: "2018", isDefault: false},
    {name: "V4", year: "2018", isDefault: false},
    {name: "V1", year: "2020", isDefault: true}
  ];

我想要得到一个结果数组，其中包含 array1 和 array2 中的所有项目，但基于名称和年份(基于 2 个键的组合)仅包含一次公共(public)项目。我必须按如下方式获取结果数组:

const array = [
    {name: "V1", year: "2018", isDefault: false},
    {name: "V2", year: "2018", isDefault: false},
    {name: "V3", year: "2018", isDefault: false},
    {name: "V4", year: "2018", isDefault: false},
    {name: "V1", year: "2019", isDefault: true},
    {name: "V1", year: "2020", isDefault: true}
  ];

请帮助我如何在 javascript 中获取它？

Answer 1

您可以将 array2 的过滤版本连接到 array1。

const array1 = [
    {name: "V1", year: "2018", isDefault: false},
    {name: "V2", year: "2018", isDefault: false},
    {name: "V3", year: "2018", isDefault: false},
    {name: "V4", year: "2018", isDefault: false},
    {name: "V1", year: "2019", isDefault: true}
];

const array2 = [
    {name: "V1", year: "2018", isDefault: false},
    {name: "V2", year: "2018", isDefault: false},
    {name: "V3", year: "2018", isDefault: false},
    {name: "V4", year: "2018", isDefault: false},
    {name: "V1", year: "2020", isDefault: true}
];

let res = array1.concat(
    array2.filter(({name, year}) => !array1.some(y => y.name === name && y.year === year))
);

console.log(res);