我有以下 JavaScript。
有没有办法让这件事变得更简单。看起来很重?
它基本上采用 12 个输入的值并根据这些值更改数组
function updatechart (){
var inputnoinsulation1 = document.getElementById("noinsulation1").value
var inputnoinsulation2 = document.getElementById("noinsulation2").value
var inputnoinsulation3 = document.getElementById("noinsulation3").value
var inputnoinsulation4 = document.getElementById("noinsulation4").value
var inputnoinsulation5 = document.getElementById("noinsulation5").value
var inputnoinsulation6 = document.getElementById("noinsulation6").value
var inputnoinsulation7 = document.getElementById("noinsulation7").value
var inputnoinsulation8 = document.getElementById("noinsulation8").value
var inputnoinsulation9 = document.getElementById("noinsulation9").value
var inputnoinsulation10 = document.getElementById("noinsulation10").value
var inputnoinsulation11 = document.getElementById("noinsulation11").value
var inputnoinsulation12 = document.getElementById("noinsulation12").value
chart1data[0].NoInsulation = (parseInt(inputnoinsulation1));
chart1data[1].NoInsulation = (parseInt(inputnoinsulation2));
chart1data[2].NoInsulation = (parseInt(inputnoinsulation3));
chart1data[3].NoInsulation = (parseInt(inputnoinsulation4));
chart1data[4].NoInsulation = (parseInt(inputnoinsulation5));
chart1data[5].NoInsulation = (parseInt(inputnoinsulation6));
chart1data[6].NoInsulation = (parseInt(inputnoinsulation7));
chart1data[7].NoInsulation = (parseInt(inputnoinsulation8));
chart1data[8].NoInsulation = (parseInt(inputnoinsulation9));
chart1data[9].NoInsulation = (parseInt(inputnoinsulation10));
chart1data[10].NoInsulation = (parseInt(inputnoinsulation11));
chart1data[11].NoInsulation = (parseInt(inputnoinsulation12));
最佳答案
for (var i = 0; i < 12; i++)
chart1data[i].NoInsulation = parseInt(document.getElementById("noinsulation" + (i + 1)).value);
应该可以。
关于javascript - 我怎样才能使这个更轻量级的javascript?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19157204/