我希望更改按住单击时按钮的图像,然后在单击释放时更改回来。我目前有一个平面图像,我希望将其更改为带有内阴影的图像,使其看起来像按下按钮,但在释放鼠标单击时变回原始平面图像。我尝试了 onmouseup 但我认为我使用它不正确。我希望 "item"
和 "item2"
在单击时保持其图像,并且可以正常工作。不过,我希望 "item3"
在鼠标释放时变回原样,或者在单击后立即变回原样。
(编辑:我是 JavaScript 新手,它不一定是 onmouseup
解决方案。如果有人可以解释如何创建一个执行此操作的函数,那就太好了。)
JS:
var onImgStp= "images/stop.png";
var onImgPnk= "images/pink.png";
var onImgMut= "images/mute.png";
var offImg= "images/green.png";
var offImgStp= "images/stop2.png";
HTML:
<img class="item" src="images/pink.png" onclick="manage(1); this.src = (this.src.endsWith(offImg)? onImgPnk : offImg);"/>
<img class="item" src="images/pink.png" onclick="manage(2); this.src = (this.src.endsWith(offImg)? onImgPnk : offImg);"/>
<img class="item" src="images/pink.png" onclick="manage(3); this.src = (this.src.endsWith(offImg)? onImgPnk : offImg);"/>
<img class="item" src="images/pink.png" onclick="manage(4); this.src = (this.src.endsWith(offImg)? onImgPnk : offImg);"/>
<img class="item" src="images/pink.png" onclick="manage(5); this.src = (this.src.endsWith(offImg)? onImgPnk : offImg);"/>
<img class="item" src="images/pink.png" onclick="manage(6); this.src = (this.src.endsWith(offImg)? onImgPnk : offImg);"/>
<img class="item" src="images/pink.png" onclick="manage(7); this.src = (this.src.endsWith(offImg)? onImgPnk : offImg);"/>
<img class="item" src="images/pink.png" onclick="manage(8); this.src = (this.src.endsWith(offImg)? onImgPnk : offImg);"/>
<img class="item2" src="images/mute.png" onclick="this.src = (this.src.endsWith(offImg)? onImgMut : offImg);"/>
<img class="item3" src="images/stop.png" onmouseup="this.src = (this.src.endsWith(offImgStp)? onImgStp : offImgStp);"/>
最佳答案
简单的解决方案
.image-swap {
cursor: pointer;
}
.image-swap>img, .image-swap:active>img:first-child {
display: none;
}
.image-swap>img:first-child, .image-swap:active>img:last-child {
display: block;
}
<div class="image-swap">
<img src="http://blog.hvidtfeldts.net/media/city7.png" />
<img src="http://blog.hvidtfeldts.net/media/city2.png" />
</div>
删除选择和拖动效果
.image-swap {
-webkit-user-select: none;
-moz-user-select: none;
-ms-user-select: none;
-o-user-select: none;
user-select: none;
cursor: pointer;
}
.image-swap>img {
pointer-events: none;
display: none;
}
.image-swap>img:first-child {
display: block;
}
.image-swap:active>img:first-child {
display: none;
}
.image-swap:active>img:last-child {
display: block;
}
<div class="image-swap">
<img src="http://blog.hvidtfeldts.net/media/city7.png" />
<img src="http://blog.hvidtfeldts.net/media/city2.png" />
</div>
平滑过渡
.image-swap {
-webkit-user-select: none;
-moz-user-select: none;
-ms-user-select: none;
-o-user-select: none;
user-select: none;
cursor: pointer;
position: relative;
}
.image-swap>img {
pointer-events: none;
transition: all 0.6s;
position: absolute;
opacity: 0;
left: 0;
}
.image-swap>img:first-child {
position: static;
opacity: 1;
}
.image-swap:active>img:first-child {
opacity: 0;
}
.image-swap:active>img:last-child {
opacity: 1;
}
<div class="image-swap">
<img src="http://blog.hvidtfeldts.net/media/city7.png" />
<img src="http://blog.hvidtfeldts.net/media/city2.png" />
</div>
如果您愿意,可以为图像提供类,例如 base-img
和 active-img
因此,您可以将 :first-child
替换为 .base-img
,将 :last-child
替换为 .active-图片
关于javascript - 按住单击时更改图像,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44414279/