javascript - 比较两个对象忽略一个键

Question

我有两个对象如下:

obj1 = {"a":"firstValue", "b":"secondValue", "c":"thirdValue157das15714daa4"} 
obj2 = {"a":"firstValue", "b":"secondValue", "c":"thirdValue1348sdfsf114sfs45fsd"}

我需要比较两个对象，忽略第三个键值对“c”。基本上比较应该返回 true 忽略 'c'

任何人都可以帮助我用 Angular 或 JavaScript 提供乐观的解决方案

提前致谢

Answer 1

简单

obj1.a == obj2.a && obj1.b == obj2.b

或者，如果 a 和 b 将是动态的，则存储 keyToIgnore

var keyToIgnore = [ "c" ];
var isEqual = Object.keys( obj1 ).every( s => keyToIgnore.includes(s) || obj1[ s ] == obj2[ s ] );

演示

var obj1 = {
  "a": "firstValue",
  "b": "secondValue",
  "c": "thirdValue157das15714daa4"
}
var obj2 = {
  "a": "firstValue",
  "b": "secondValue",
  "c": "thirdValue1348sdfsf114sfs45fsd"
}
var keyToIgnore = [ "c" ];
var fnCompare = ( obj1, obj2 ) => Object.keys(obj1).every(s => keyToIgnore.includes(s) || obj1[s] == obj2[s]);

console.log( fnCompare( obj1, obj2 ) )