我需要减少对象数组,但减少对象中的特定 key
属性,并将具有相同 key
值的所有对象放入一个数组中在关联的 value
数组中。
我需要的示例:
对象
var obj1 = {
name: "server1",
type: "http",
port: "8080"
}
var obj2 = {
name: "server2",
type: "https",
port: "8443"
}
var obj3 = {
name: "server3",
type: "http",
port: "80"
}
// Place objects in an array (as interm step)
var array = [obj1, obj2, obj3];
使用上面的代码,我尝试了
var map = new Map(array.map(server => [server.type, server]));
但这最终给了我:
0: {"http" => Object}
key: "http"
value:
name: "server3"
port: "80"
type: "http"
1: {"https" => Object}
key: "https"
value:
name: "server2"
port: "8443"
type: "https"
但是我需要是:
0: {"http" => Object}
key: "http"
value:[
{
name: "server1"
port: "8080"
type: "http"
},
{
name: "server3"
port: "80"
type: "http"
},
1: {"https" => Object}
key: "https"
value:
name: "server2"
port: "8443"
type: "https"
因此,我可以遍历每个类型
,找到所有唯一值,以此作为类型创建每个对象的列表,然后将其添加到映射中,但这对于一个简单的任务来说似乎太多了。
有没有更快/更方便的方法来缩短这个时间?
最佳答案
我不确定 map 在这里是否合适。您可以使用简单的 forEach
并检查当前键是否已存在于数组中。如果没有,则使用当前项目创建一个新对象并检查下一个。
类似这样的事情:
var obj1 = {
name: "server1",
type: "http",
port: "8080"
}
var obj2 = {
name: "server2",
type: "https",
port: "8443"
}
var obj3 = {
name: "server3",
type: "http",
port: "80"
}
// Place objects in an array (as interm step)
var array = [obj1, obj2, obj3];
let output = {};
array.forEach((item) => {
// the item does not exists, we create it.
if(!output[item.type]) {
output[item.type] = {key: item.type, value: []};
}
// in either case, we push the current item in the value.
// of the current output key.
output[item.type].value.push(item);
});
// we are using Object.values() because we do not want the keys
// used to generate the output.
console.log(Object.values(output));
关于javascript - 将对象数组减少为键值对映射,保留值数组中的重复条目,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59879085/