javascript - 如何防止 Fine-Uploader 出现错误警报？

Question

有什么方法可以防止触发 onError 回调时发出警报吗？

我只需要捕获错误并以不同的方式显示它

Answer 1

是的，只需覆盖 showMessage option .

例如:

var uploader = new qq.FineUploader({
    request: {
        endpoint: 'my/endpoint'
    },
    callbacks: {
        onError: function(fileId, filename, reason, maybeXhr) {
            //do something with the error
        }
    },
    showMessage: function(message) {
        //either include an empty body, or some other code to display (error) messages
    }
});