javascript - 根据另一个数组的空元素从一个数组中删除元素

Question

仅当另一个数组中存在空元素时，我才想从数组中删除元素。我有这个:

var fruits = ["Banana", "Naranja", "Manzana", "Mango", "Fresa", "Limón", "Lima", "Sandia"];
var vegetales = ["", "Ajo", "", "Cebolla", "Tomate", "", "", "Zanahoria"];
    
// The output should be this:
// ["Naranja", "Mango", "Fresa", "Sandia"]
function myFunction() {
  for (var i in vegetales) {
    if (vegetales[i] == '') {
      frutaAeliminar = fruits[i];
      indexFruta = fruits.indexOf(frutaAeliminar);
      if (indexFruta != -1) {
        fruits.splice(indexFruta, 1)
      }
    }
  }
  console.log(fruits);
}

myFunction();

Answer 1

使用 ES6 的示例

使用Array.filter在三元中使用 && 可以让我们在不需要时不必担心 else

const fruits = ["Banana", "Naranja", "Manzana", "Mango", "Fresa", "Limón", "Lima", "Sandia"];
const vegetales = ["", "Ajo", "", "Cebolla", "Tomate", "", "", "Zanahoria"];

/* only pick if corresponding array item does not equal '' */ 
const newArray = fruits.filter((fruit, idx) => (vegetales[idx] !== '' && fruit))

console.log(newArray)