如果这个问题已经被问过，请原谅我；我已经在网站上搜索过这个问题，但还没有偶然发现。
我正在创建一个猜词游戏，但我在使用最后一个函数时遇到了问题。函数参数是用户输入的字符(“character”)、随机生成的单词(“word”)以及该单词的加扰版本(“scrmbldword”)。例如，单词可以是“chilly”，并且乱序版本将具有相应数量的下划线“______”。该函数的作用是获取用户输入，扫描“单词”中的该字母，如果在单词中找到该字母，则将“scrmbldword”的下划线替换为相应的字母。
例如，单词是“chilly”，用户输入的字符是“l”；我需要将 scrmbldword 变为“___ll_”。
function unscrambledWord(character, scrmbldword, word) {
for (k = 0; k < word.length; k++) {
if (character == word[k]) {
var tempLetter = word[k];
console.log(tempLetter)
tempWord = scrmbldword.replace(scrmbldword[k], character);
console.log(tempWord);
}
}
}
感谢您的所有答案，但是当我将它们复制并粘贴到我的代码中时，它们不起作用。我试图理解您的各种答案背后的代码，以便我可以自己编辑它们，但在大多数情况下我不明白。如果我提供更多背景信息，也许会对大家有所帮助，所以这是我的完整文件...
<!DOCTYPE html>
<html lang="en-us">
<head>
<meta charset="UTF-8">
<title>Word Guess Game</title>
</head>
<body>
<div>
<p id="directions-text">Type any letter to start playing</p>
<p id="userchoice-text"></p>
<p id="userguesslist-text"></p>
<p id="unscrambledword-text"></p>
</div>
<script type="text/javascript">
var userGuesses = [];
var unknownWord = "";
function wordGenerator() {
var computerChoices = ["lowly", "start", "chilly", "bun", "bead", "friend", "return", "view", "cloth", "frogs", "celery", "basin", "stand", "special", "broad", "abaft", "plead", "quartz", "mark", "tempt", "shop", "stone", "scorch", "taboo", "hoax", "spiffy", "insure"];
var cpuWord = computerChoices[Math.floor(Math.random() * computerChoices.length)];
console.log(cpuWord);
return cpuWord;
};
var computerWord = wordGenerator();
function scrambledWord(string) {
var knownWord = ""
if (string.length == 3) {
knownWord = "___"
} else if (string.length == 4) {
knownWord = "____"
} else if (string.length == 5) {
knownWord = "_____"
} else if (string.length == 6) {
knownWord = "______"
} else if (string.length == 7) {
knownWord = "_______"
}
return knownWord;
}
var unknownWord = scrambledWord(computerWord);
var directionsText = document.getElementById("directions-text");
var userChoiceText = document.getElementById("userchoice-text");
var userGuessList = document.getElementById("userguesslist-text");
var unscrambledWordText = document.getElementById("unscrambledword-text");
document.onkeyup = function (event) {
var userGuess = event.key;
if ((userGuess === "a") || (userGuess === "b") || (userGuess === "c") || (userGuess === "d") || (userGuess === "e") || (userGuess === "f") || (userGuess === "g") || (userGuess === "h") || (userGuess === "i") || (userGuess === "j") || (userGuess === "k") || (userGuess === "l") || (userGuess === "m") || (userGuess === "n") || (userGuess === "o") || (userGuess === "p") || (userGuess === "q") || (userGuess === "r") || (userGuess === "s") || (userGuess === "t") || (userGuess === "u") || (userGuess === "v") || (userGuess === "w") || (userGuess === "x") || (userGuess === "y") || (userGuess === "z")) {
userGuesses.push(userGuess);
directionsText.textContent = "";
userChoiceText.textContent = "You chose: " + userGuess;
userGuessList.textContent = "You have guessed: " + userGuesses;
unscrambledWordText.textContent = "The word is: " + unknownWord;
wordChecker(userGuess)
} else {
alert("You did not enter an alphabetical character.")
}
};
function wordChecker(input) {
if (computerWord.includes(input)) {
alert("You guessed a correct character")
unscrambledWord(input, unknownWord, computerWord)
} else {
alert("You guessed an incorrect character")
}
}
function unscrambledWord(character, scrmbldword, word) {
for (k = 0; k < word.length; k++) {
if (character == word[k]) {
var tempLetter = word[k];
console.log(tempLetter)
tempWord = scrmbldword.replace(scrmbldword[k], character);
console.log(tempWord);
}
}
}
最佳答案
据我了解，你可以试试这个
function unscrambledWord(character, word, scrmbldword = "_".repeat(word.length)) {
return [...scrmbldword].map((d, i) => d == '_' && word[i] == character ? character : d).join('')
}
console.log(unscrambledWord('l', 'chilly'))关于javascript - 替换字符串中的值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/53198115/