在我的应用程序中,MongoDB 3.2.4 在自定义端口上运行,我想实现我的应用程序将尝试在自定义端口上访问 MongoDB 的逻辑,如果失败,它将使用默认的 27018
端口。
为此,我使用了以下代码:
String mongoClientURI = "mongodb://" + DB_SRV_USR + ":" + DB_SRV_PWD + "@" + DB_URL + ":" + DB_PORT_CUS + "/" + dbName;
MongoClientURI connectionString = new MongoClientURI(mongoClientURI);
// enable SSL connection
MongoClientOptions.builder().sslEnabled(true).build();
if (this.mongoClient == null) {
this.mongoClient = new MongoClient(connectionString);
}
// create database if doesn't exist
MongoDatabase mdb = this.mongoClient.getDatabase(dbName);
try {
this.mongoClient.getAddress();
} catch (com.mongodb.MongoSocketOpenException e) {
System.out.println("Switch to default port");
/*…use default port logic…*/
}
问题是没有捕获到这个异常。 尽管 MongoDB 抛出以下异常:
com.mongodb.MongoSocketOpenException: Exception opening socket at com.mongodb.connection.SocketStream.open(SocketStream.java:63) at com.mongodb.connection.InternalStreamConnection.open(InternalStreamConnection.java:114) at com.mongodb.connection.DefaultServerMonitor$ServerMonitorRunnable.run(DefaultServerMonitor.java:128) at java.lang.Thread.run(Thread.java:745) Caused by: java.net.ConnectException: Connection refused: connect at java.net.DualStackPlainSocketImpl.waitForConnect(Native Method) at java.net.DualStackPlainSocketImpl.socketConnect(DualStackPlainSocketImpl.java:85) at java.net.AbstractPlainSocketImpl.doConnect(AbstractPlainSocketImpl.java:350) at java.net.AbstractPlainSocketImpl.connectToAddress(AbstractPlainSocketImpl.java:206) at java.net.AbstractPlainSocketImpl.connect(AbstractPlainSocketImpl.java:188) at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:172) at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:392) at java.net.Socket.connect(Socket.java:589) at com.mongodb.connection.SocketStreamHelper.initialize(SocketStreamHelper.java:50) at com.mongodb.connection.SocketStream.open(SocketStream.java:58) ... 3 more
我的 try-catch
表达式无法捕获此异常。
我尝试了多种方法,比如捕捉:
异常
运行时异常
MongoSocketOpenException
MongoException
MongoCommandException
它们都不起作用。
我的问题:
如何检查 MongoDB 连接是否建立?
如何捕获异常
MongoSocketOpenException
?
最佳答案
我使用这段代码来检查连接:
try { mongo.getAddress(); } catch (Exception e) { System.out.println("Database unavailable!"); mongo.close(); return; }
不确定我的猜测是
this.mongoClient.getAddress();
不会抛出该异常,但我真的不知道
编辑:我通过以下方式初始化它:
Builder builder = MongoClientOptions.builder().connectTimeout(3000);
MongoClient mongo = new MongoClient(new ServerAddress("192.168.0.1", 3000), builder.build());
关于java - 如何检查是否与 Java 建立了 MongoDB 连接?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36527991/