我有一些 PHP 代码，其中使用了 codeigniter。如何检查标记为检查的文件的有效性？我的代码如下。
您能否告诉我如何检查项目是否已选中并相应地强制验证？
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<script type="text/Javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<link rel="stylesheet" type="text/css" href="<?php echo base_url(); ?>/site.css"></link>
</head>
<body>
<script type="text/Javascript">
$(function () {
$('.checkall').click(function () {
$(this).parents('fieldset:eq(0)').
find(':checkbox').attr('checked', this.checked);
});
});
</script>
<? $attributes = array('class' => '', 'id' => ''); ?>
<? echo form_open('ShoppingListController', $attributes); ?>
<div class="divTable">
<fieldset>
<!-- these will be affected by check all -->
<div class="divRow">Product Name | Quantity | Packages</div>
<div class="divRow"><input type="checkbox" size="100" class="checkall"> Check all</div>
<br>
<?php foreach ($records as $rec) {
?>
<div class="divRow"><input type="checkbox">
<input size="5" type="hidden" value="<? echo $rec->id; ?>" name="id"></input>
<input size="20" type="text" value="<? echo $rec->name; ?>" name="name"></input>
<label for="quantity">Value <span class="required">*</span></label>
<span class="required"><?php echo form_error('quantity'); ?></span>
<input size="5" type="text" value="" name="quantity"></input>
<select name="package">
<option name="case">Case</option>
<option name="box">Box</option>
<option name="box">Single Bottle</option>
</select>
</div>
<br>
<?
}
?>
</fieldset>
</div>
<div><input type="submit" name="submit"/></div>
</form>
</body>
最佳答案
您可以使用下面的代码:
var divRows = $('.divRow');
var count = divRows.length;
divRows.each(function() {
if ($(this).find('input[type=checkbox]').is(':checked')) {
count--;
}
});
if (count != 0) {
alert(count + ' checkboxes not checked');
}
关于php - JavaScript 仅用于验证已检查的提交，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/15465340/