我试图发布从每个下拉菜单中获得的值,这是一个 n 级,但是我最多使用 3 个值。如何发布从每个选择中获得的每个值?
<?php
include('dbcon.php');
if($_REQUEST)
{
$id = $_REQUEST['parent_id'];
$query = "select * from ajax_categories where pid = ".$id;
$results = @mysql_query( $query);
$num_rows = @mysql_num_rows($results);
if($num_rows > 0)
{?>
<select name="sub_category" class="parent">
<option value="" selected="selected">-- Sub Category --</option>
<?php
while ($rows = mysql_fetch_assoc(@$results))
{?>
<option value="<?php echo $rows['id'];?>"><?php echo $rows['category'];?></option>
<?php
}?>
</select>
<?php
}
else{echo '<label style="padding:7px;float:left; font-size:12px;">No Record Found !</label>';}
}
?>
http://www.99points.info/2010/12/n-level-dynamic-loading-of-dropdowns-using-ajax-and-php/
最佳答案
像这样更改您的选择选项
<select name="sub_category" class="parent">
<option value="" selected="selected">-- Sub Category --</option>
while ($rows = mysql_fetch_assoc(@$results))
{?>
echo '<option value="'.$row['id'].'">'.$rows['category'].'</option>';
<?php
}?>
</select>
<?php
}
else{echo '<label style="padding:7px;float:left; font-size:12px;">No Record Found !</label>';}
}
</select>
关于javascript - 动态下拉菜单 POST,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19059075/